Answer: Option D
Step-by-step explanation:
Note that the projectile height as a function of time is given by the quadratic equation
To find the maximum height of the projectile we must find the maximum value of the quadratic function.
By definition the maximum value of a quadratic equation of the form
is located on the vertex of the parabola:
Where 
In this case the equation is:
Then
So:
Answer:
b+3a
Step-by-step explanation:
MN=AN+AM
AN=0.5*AB
AB=OA+OB=4a+2b
AN=2a+b
AM=OA-OM=4a-3a=a
MN=2a+b+a=3a+b
I think the answer is eight because the answer should be eight probably ate it is the best answer I think it is best
320 i believe... the original answer was 317.52
Given the equation:
Let's identify the type of polar graph for the equation.
To identify the type of polar graph, use the formula below to get the Cartesian form:
Thus, we have:
![(x^2+y^2)=3\sqrt[]{x^2+y^2}-5x](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%3D3%5Csqrt%5B%5D%7Bx%5E2%2By%5E2%7D-5x)
We have the graph of the equation below:
We can see the graph forms a Limacon with an inner loop.
Therefore, the type of polar graph for the given equation is a limacon with inner loop.
ANSWER:
