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Ket [755]
3 years ago
14

A small office experiences frequent power outages. Users at the location reports that after rebooting their Windows workstations

following each power outage, they can no longer find or open files stored on the network. Which of the actions must a technician perform to resolve this issue in the future?
Physics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

Explanation:

Usually office's networks works using the TCP/IP protocol, this mean that each workstation has an assigned IP. This IP are the directions gave to each computer on the network,

This IP are usually asigned by a DHCP Server. Servers every time a new device connect to the Network, assigns to it an IP, this way every Computer will know how to send or request information from that Computer.

In the TCP/IP protocol is not posibble for two computer to have the same IP. This causes what it call IP Conflict, IP Conflict make imposible the comunications between those devices and the Network.

On Power outages all the Computer are turn off, because of this they disconnect from the Network and need to requests IP one more time to gain comunication,

We this in mind, we can predict that frequent power outages can cause for all the Computer in the Network to request new IPs very frequently this will cause IP Conflict in several units, disconnecting them from the network and making them no longer able to find files on the network. To fix this, what can be done it to establish Static IP to every workstation, this way we they request a new IP, the DHCP Serve will assign them the same IP form every session.

This way, the IP Conficlt can end. Another option is to make the DHCP to assign new IP to every unit one more time, eliminating the machines with same IP.

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2 years ago
a scale model of the solar system where 50 cm represents 1.0x10 to the fifth km is actual distance what would be the dimension o
Fofino [41]

The distance between Mars and the Sun in the scale model would be 1140 m

Explanation:

In this scale model, we have:

x_1 = 50 cm represents an actual distance of

d_1 = 1.0\cdot 10^5 km

The actual distance between Mars and the Sun is 228 million km, therefore

d_2=228\cdot 10^6 km

On the scale model, this would corresponds to a distance of x_2.

Therefore, we can write the following proportion:

\frac{x_1}{d_1}=\frac{x_2}{d_2}

And solving for x_2, we find:

x_2=\frac{x_1 d_2}{d_1}=\frac{(50)(228\cdot 10^6)}{1\cdot 10^5}=1.14\cdot 10^5 cm = 1140 m

Learn more about distance:

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4 0
3 years ago
A woman of mass 50 kg is swimming with a velocity of 1.6 m/s. If she stops stroking and glides to a stop in the water, what is t
Snezhnost [94]

Answer:

Impulse of force = -80 Ns

Explanation:

<u>Given the following data;</u>

Mass = 50kg

Initial velocity = 1.6m/s

Since she glides to a stop, her final velocity equals to zero (0).

Now, we would find the change in velocity.

Change \; in \; velocity = final \; velocity - initial \; velocity

Substituting into the equation above;

Change in velocity = 0 - 1.6 = 1.6m/s

Impulse \; of \; force = mass * change \; in \; velocity

Substituting into the equation, we have;

Impulse \; of \; force = 50 * -1.6

<em>Impulse of force = -80 Ns</em>

<em>Therefore, the impulse of the force that stops her is -80 Newton-seconds and it has a negative value because it is working in an opposite direction, thus, bringing her to a stop. </em>

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2 years ago
Blake is setting up his tent at a renaissance fair. If the tent is 8 feet tall and the tether can be staked no more than 2 feet
Mariana [72]
The stake, height and tether length of the tent form a right angle triangle where the tether length is the hypotenuse.
Applying Pythagoras theorem:
length² = height² + (stake distance)²
length = √(8² + 2²)
length = 8.5 feet
3 0
3 years ago
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