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Ket [755]
3 years ago
14

A small office experiences frequent power outages. Users at the location reports that after rebooting their Windows workstations

following each power outage, they can no longer find or open files stored on the network. Which of the actions must a technician perform to resolve this issue in the future?
Physics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

Explanation:

Usually office's networks works using the TCP/IP protocol, this mean that each workstation has an assigned IP. This IP are the directions gave to each computer on the network,

This IP are usually asigned by a DHCP Server. Servers every time a new device connect to the Network, assigns to it an IP, this way every Computer will know how to send or request information from that Computer.

In the TCP/IP protocol is not posibble for two computer to have the same IP. This causes what it call IP Conflict, IP Conflict make imposible the comunications between those devices and the Network.

On Power outages all the Computer are turn off, because of this they disconnect from the Network and need to requests IP one more time to gain comunication,

We this in mind, we can predict that frequent power outages can cause for all the Computer in the Network to request new IPs very frequently this will cause IP Conflict in several units, disconnecting them from the network and making them no longer able to find files on the network. To fix this, what can be done it to establish Static IP to every workstation, this way we they request a new IP, the DHCP Serve will assign them the same IP form every session.

This way, the IP Conficlt can end. Another option is to make the DHCP to assign new IP to every unit one more time, eliminating the machines with same IP.

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A good soccer player can kick the ball up to 25 m/sec. A soccer ball has a mass of 800 grams (0.8 kg). What force must a goalie
Oksana_A [137]

Answer:

200 N

Explanation:

Applying,

The force a golie must exert on the ball is,

F = ma...................... Equation 1

Where m = mass of the ball, a = acceleration of the ball.

But,

a = Δv/t............... Equation 2

Where Δv = change in velocity, t = time.

Substitute equation 2 into equation 1

F = m(Δv/t)............... Equation 3

From the question,

Given: m = 0.8 g, t = 0.1 s, Δv = 25 m/s

Substitute these values into equation 3

F = 0.8×25/0.1

F = 200 N

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In which type of Eclipse do u see the Sun in the form of a ring
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8 0
3 years ago
The acceleration of gravity at the surface of Moon is 1.6 m/s2 . A 5.0 kg stone thrown upward on Moon reaches a height of 20 m.
kramer

Answer:

(a) 8 m/s

(b) 5 s

Explanation:

(a)

Using,

V² = U²+2gh ......................... Equation 1

Where V = final velocity, U = Initial velocity, g = acceleration due to gravity on the surface of the moon, h = height reached.

Given: V = 0 m/s ( At it's maximum height), g = -1.6 m/s² ( as its moves against gravity), h = 20 m.

Substitute into equation 1

0 = U²+[2×20×(-1.6)]

-U² = - 64

U² = 64

U = √64

U = 8 m/s.

(b)

V = U +gt.................... Equation 2

Where t = time to reach the maximum height.

Given: V = 0 m/s ( At the maximum height), g = -1.6 m/s² ( Moving against gravity), U = 8 m/s.

Substitute into equation 2

0 = 8+(-1.6t)

-8 = -1.6t

-1.6t = -8

t = -8/-1.6

t = 5 s.

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3 years ago
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