Answer:
The skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.
Explanation:
To solve the problem it is necessary to go back to the theory of conservation of momentum, specifically in relation to the collision of bodies. In this case both have different addresses, consideration that will be understood later.
By definition it is known that the conservation of the moment is given by:
Our values are given by,
As the skater 1 run in x direction, there is not component in Y direction. Then,
Skate 1:
Skate 2:
Then, if we applying the formula in X direction:
m_1v_{x1}+m_2v_{x2}=(m_1+m_2)v_{fx}
75*5.45-75*1.41=(75+75)v_{fx}
Re-arrange and solving for v_{fx}
v_{fx}=\frac{4.04}{2}
v_{fx}=2.02m/s
Now applying the formula in Y direction:
Therefore the skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.
Small evidence is also called trace evidence.
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Answer:
magnification = - 30
overall magnification = -240
Explanation:
given data
Focal length of microscope objective f = 0.150 cm
Object distance from microscope objective do = 0.155 cm
magnification by eyepiece = 8 ×
to find out
What magnification is produced and overall magnification
solution
we consider here Image distance from microscope objective is = di
so that
Magnification produced by objective will be = - 
so we find here di by given equation that is
..................1
di = 4.65 cm
so that magnification by object will be
magnification = -
magnification = - 
magnification = - 30
and
overall magnification will be
overall magnification = magnification by objective × magnification by eyepiece ........................2
overall magnification = -30 × 8
overall magnification = -240
