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4 years ago

As an ice cube melts, its molecules

Physics

1 answer:

fomenos4 years ago

3 0

Answer:

A. absorb heat energy and move farther apart

Explanation:

The answer is A since when a ice cube takes in heat, it changes form and melts down to a liquid : water.

The molecules in water are farther apart since they are moving around alot but can be contained in a container.

You might be interested in

if the force of friction is acting on the sliding crate is 100 N how much force will be applied to maintain a constant velocity?

djverab [1.8K]

"Constant velocity" means zero acceleration, which means zero net force. So there must be100N pulling on the crate to cancel the 100N of friction force.

5 0

4 years ago

When a 100-N force acts horizontally on an 8.0-kg chair, the chair moves at a constant speed across the level floor. Which state

TiliK225 [7]

Answer:

The applied force is greater than the frictional force.

Explanation:

the chair moves at a constant speed therefore, the answer is not A or C.

if there is no friction then the chair would accelerate and it would not be at a constant speed.

hence, the only possible answer is B.

7 0

3 years ago

PLEASEE GUYS HELP I BEG YOU

raketka [301]

0.520155077123917 i believe?? hope this helps

7 0

3 years ago

Find the ratio of the lengths of the two mathematical pendulums, if the ratio of periods is 1.5

juin [17]

Answer:

The ratio of lengths of the two mathematical pendulums is 9:4.

Explanation:

It is given that,

The ratio of periods of two pendulums is 1.5

Let the lengths be L₁ and L₂.

The time period of a simple pendulum is given by :

$T=2\pi \sqrt{\dfrac{l}{g}}$

$T^2=4\pi^2\dfrac{l}{g}\\\\l=\dfrac{T^2g}{4\pi^2}$

Where

l is length of the pendulum

$l\propto T^2$

$\dfrac{l_1}{l_2}=(\dfrac{T_1}{T_2})^2$ ....(1)

ATQ,

$\dfrac{T_1}{T_2}=1.5$

Put in equation (1)

$\dfrac{l_1}{l_2}=(1.5)^2\\\\=\dfrac{9}{4}$

So, the ratio of lengths of the two mathematical pendulums is 9:4.

3 0

3 years ago

From Gauss's law, the electric field set up by a uniform line of charge is given by the following expression where is a unit vec

Evgesh-ka [11]

Answer:

$\Delta V=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})$

Explanation:

Using the Gauss Law, we obtain the electric Field for a uniform large line of charge:

$2\pi r L*E=\lambda *L/\epsilon_{o}$

$E=\lambda /\(2 \pi* r *\epsilon_{o})$

We calculate the potential difference from the electric field:

$\Delta V=-\int\limits^{r_{1}}_{r_{2}} E \, dr =-\int\limits^{r_{1}}_{r_{2}} \lambda dr/ (2\pi*r*\epsilon_{o})=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})$

5 0

4 years ago