Given: The systolic arterial blood pressure observed for 20 dogs is normally distributed with a mean of 152 mm of mercury (Hg) and a standard deviation of 18 mm of Hg.
To find: P(100 < 152)
Method: Calculation of Z-Score followed by the probability or area of the bell curve at X = 100.
Solution:
Mean u = 152, std s = 18
Z score = 
The value of P(100<152) is calculated by looking at the value of Z in the Z score for the standard normal distribution given in the image.
P(Z=-2.89) = 0.0019
The P(Z = -2.89) corresponds to the area in the left tail of the bell curve.
Thus the probability of 100 mm Hg blood pressure is 0.0019.
Answer:
they will move into the cell
We use Chargaff's rule to get the answer.
[A] + [G] = [C]+ [T].
[A] + [G] + [C] + [T] = 100%
Where is A is Adenine, G is Gaunine, T is Thymine and C is Cytosine.
In DNA, Adenine always pairs with Thymine, and Guanine always pairs with Cytosine.
Therefore if Thymine is 35%, then Adenine will also be 35% to make 70% in total.
The remaining percentage will be 100% - 70% = 30%.
The 30% will be shared equally among Cytosine and Guanine, at 15% each. Therefore Cytosine will be 15%
Reduce your risk of heart failure or also known as heart attack :)) -litliam✨