All categories

3 years ago

Which of the following particles occupy a zone relatively far from the nucleus of an atom?

Physics

2 answers:

creativ13 [48]3 years ago

8 0

Electrons is the answer

daser333 [38]3 years ago

3 0

Electrons hope this helps

You might be interested in

The moon's illumination changes in a periodic way that can be modeled by a trigonometric function. On the night of a full moon,

kupik [55]

Answer:

$L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125$

Explanation:

The expression for the trigonometric function is :

L(t) = A (cos (B(t - C)))+ D ----- equation (1)

where ;

$A = \frac{max-min}{2}$

$A = \frac{0.25-0}{2}$

A = 0.125

D = $\frac{0+.025}{2}$

D = 0.125

Period of the lunar cycle = 29.53

Then;

$\frac{2 \pi}{B} = 29.53$

$29.53 \ \ B = 2 \pi$

$B = \frac{2 \pi}{29.53}$

$B = \frac{\pi}{29.53}$

Also; we known that December 25 is 7 days before January 1.

Then L(-7) = 0.025

Plugging all the values into trigonometric function ; we have:

$0.125 ( cos ( \frac{\pi}{14.765}((-7)-C)))+0.125 = 0.25 \\ \\ \\ ( cos ( \frac{\pi}{14.765}((-7)-C))) = \frac{0.25-0.125}{0.125}$

$( cos ( \frac{\pi}{14.765}((-7)-C))) = 1$

$( \frac{\pi}{14.765}((-7)-C))= cos^{-1} (1)$

$}((-7)-C))=0$

$C= -7$

$L(t) = 0.125 (cos (\frac{\pi}{14.765}(t-(-7))) + 0.125$

$L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125$

7 0

3 years ago

A dolphin swims 1.85 km/h how far has the dolphin traveled after 0.60 h

user100 [1]

Answer:

1.11 km

Explanation:

Distance = rate × time

d = 1.85 km/h × 0.60 h

d = 1.11 km

6 0

3 years ago

Io, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plume

Mamont248 [21]

Answer:

1331.84 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement = 490 km

a = Acceleration

g = Acceleration due to gravity = 1.81 m/s² = a

From equation of linear motion

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -1.81\times 490000}\\\Rightarrow u=1331.84\ m/s$

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km

3 0

4 years ago

Read 2 more answers

What is the molar mass of C8H10N4O2

lesya [120]

Answer:

194,22g/mol

Explanation:

8*12,01+10*1,01+4*14,01+2*16=194,22g/mol

3 0

3 years ago

Read 2 more answers

The Milky Way and Andromeda galaxies are members of the Local Group, a cluster of more than 50 galaxies spread across a spherica

fenix001 [56]

Answer:

2400 cm

Explanation:

The milky way has diameter of 100000 light years.

$100000\ ly=24\ cm\\\Rightarrow 1\ ly=\frac{24}{100000}\ cm$

The local group is the collection of galaxies which includes the milky way.

10 million light years is the diameter of the local group.

$10\times 10^6\ ly=10\times 10^6\times \frac{24}{100000}\ cm\\\Rightarrow 10\times 10^6\ ly=2400\ cm$

Hence, the diameter of the scale model of the local group would be 2400 cm

5 0

3 years ago