Question

The temperature of an object is changed when heat is added to or extracted from it. Determine the final temperature (in °C) of a 65.0 g mass of aluminum initially at 60.0°C if 1,050 J of heat energy is extracted from it. The specific heat of aluminum is 900 J/(kg · °C).

Answer 1

Answer:

$42.1^{\circ}C$

Explanation:

The heat extracted from the aluminium is given by:

$Q=mC_s (T_f-T_i)$

where we have

Q = -1050 J is the heat extracted

m = 65.0 g = 0.065 kg is the mass

Cs = 900 J/kgC is the specific heat of aluminum

$T_i = 60.0^{\circ}$ is the initial temperature

By solving for $T_f$, we find the final temperature:

$T_f = \frac{Q}{m C_s}+T_i=\frac{-1050 J}{(0.065 kg)(900 J/kg C)}+60.0^{\circ}C=42.1^{\circ}C$