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IrinaVladis [17]
3 years ago
15

Io, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plume

s of matter over 500 km high. Due to the satellite's small mass, the acceleration due to gravity on Io is only 1.81 m/s2, and Io has no appreciable atmosphere. Assume that there is no variation in gravity over the distance traveled. Part A What must be the speed of material just as it leaves the volcano to reach an altitude of 490 km
Physics
2 answers:
svetlana [45]3 years ago
4 0

Answer:

1.33 km/s

Explanation:

acceleration due to gravity, g = 1.81 m/s²

height, h = 490 km = 490000 m

Let u is the initial speed and the final speed is zero.

use third equation of motion

v² = u² - 2 g h

0 = u² - 2 x 1.81 x 490000

u² = 1773800

u = 1331.84 m/s

u = 1.33 km/s

Thus, the initial speed of the material is 1.33 km/s.

Mamont248 [21]3 years ago
3 0

Answer:

1331.84 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement = 490 km

a = Acceleration

g = Acceleration due to gravity = 1.81 m/s² = a

From equation of linear motion

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -1.81\times 490000}\\\Rightarrow u=1331.84\ m/s

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km

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Dima020 [189]

Answer:

0.43 s

Explanation:

speed (s) = 95 mi/h = 95 x 1600/3600 = 42.5 m/s  (converting to m/s)

distance (d) = 60 ft 6 inches = (60 x 0.3048) + (6 x 0.025) = 18.44 m (converting to meters)

speed = distance / time

time = distance / speed = 18.44 / 42.5 = 0.43 s

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3 years ago
De la 2surse coerente aflate la distanta d=2 metri una de alta se propaga intrun mediu elastic unde cu viteza =340 m/s.la distan
Alja [10]

<u>Explanation</u>:

The text is in Romanian language, however here's a clearer rendering which reads;

<em>"From 2 coherent sources at a distance d = 2 meters from each other, it propagates in an elastic medium where with velocity = 340 m/s. At a distance L = 4 meters from the middle between sources perpendicular to the segment joining them a maximum of interference and the next at a distance of 1.5 meters from it on the line parallel to the one on which the sources are located. What is the frequency of oscillation of the sources?."</em>

5 0
4 years ago
Do you think scientists will ever be able to recreate a living creature from the distant past successfully?
lilavasa [31]
Are we talking about extinct?

I think it could be possible. However, the creature may not last long. Creatures from the distant past died off for a reason, they couldn't survive. So, with the sudden change in environment, they won't last long, especially if they didn't last in the past.
3 0
3 years ago
Read 2 more answers
Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
shepuryov [24]

Answer:

b) TA = TB = TC

Explanation:

  • When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
  • During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
  • The equilibrium condition will be reached when the following equation be met:

       \Delta Q = c_{st}* m_{A} * (T_{fin}  - T_{0A} ) = c_{st}* m_{B} * (T_{0B}  - T_{fin} )

  • Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for  Tfin, as follows:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\  2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
  • When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
  • So, option b) is the right one.
8 0
3 years ago
A5 kg frisbee is thrown from rest to a final speed of 12 m/s. What is the impulse of the frisbee?
lesya692 [45]

Answer:

60kgm/s

Explanation:

Given parameters:

Mass of frisbee  = 5kg

Final speed  = 12m/s

Unknown:

Impulse of the frisbee  = ?

Solution:

The impulse of the frisbee is the same as the change in momentum.

It is given as:

 Impulse  = mass (Final velocity  -  Initial velocity)

 Impulse  = 5(12  - 0)  = 60kgm/s

3 0
3 years ago
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