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IrinaVladis [17]
4 years ago
15

Io, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plume

s of matter over 500 km high. Due to the satellite's small mass, the acceleration due to gravity on Io is only 1.81 m/s2, and Io has no appreciable atmosphere. Assume that there is no variation in gravity over the distance traveled. Part A What must be the speed of material just as it leaves the volcano to reach an altitude of 490 km
Physics
2 answers:
svetlana [45]4 years ago
4 0

Answer:

1.33 km/s

Explanation:

acceleration due to gravity, g = 1.81 m/s²

height, h = 490 km = 490000 m

Let u is the initial speed and the final speed is zero.

use third equation of motion

v² = u² - 2 g h

0 = u² - 2 x 1.81 x 490000

u² = 1773800

u = 1331.84 m/s

u = 1.33 km/s

Thus, the initial speed of the material is 1.33 km/s.

Mamont248 [21]4 years ago
3 0

Answer:

1331.84 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement = 490 km

a = Acceleration

g = Acceleration due to gravity = 1.81 m/s² = a

From equation of linear motion

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -1.81\times 490000}\\\Rightarrow u=1331.84\ m/s

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km

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The position vector of P is \vec P =(0, 2,4).

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The distance vector from P to Q is define by the following vectorial expression:

\overrightarrow{PQ} = \vec Q - \vec P (1)

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\|\overrightarrow{PQ}\| = \sqrt{(-3)^{2}+(-1)^{2}+1^{2}}

\|\overrightarrow{PQ}\|=\sqrt{11}

Second Method - Dot Product:

\|\overrightarrow{PQ}\| = \sqrt{\overrightarrow{PQ}\,\bullet\,\overrightarrow{PQ}} (2)

\|\overrightarrow{PQ}\| = \sqrt{(-3,-1,1)\,\bullet (-3,-1,1)}

\|\overrightarrow{PQ}\|=\sqrt{11}

The distance between P and Q is \|\overrightarrow{PQ}\|=\sqrt{11}.

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