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IrinaVladis [17]
3 years ago
15

Io, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plume

s of matter over 500 km high. Due to the satellite's small mass, the acceleration due to gravity on Io is only 1.81 m/s2, and Io has no appreciable atmosphere. Assume that there is no variation in gravity over the distance traveled. Part A What must be the speed of material just as it leaves the volcano to reach an altitude of 490 km
Physics
2 answers:
svetlana [45]3 years ago
4 0

Answer:

1.33 km/s

Explanation:

acceleration due to gravity, g = 1.81 m/s²

height, h = 490 km = 490000 m

Let u is the initial speed and the final speed is zero.

use third equation of motion

v² = u² - 2 g h

0 = u² - 2 x 1.81 x 490000

u² = 1773800

u = 1331.84 m/s

u = 1.33 km/s

Thus, the initial speed of the material is 1.33 km/s.

Mamont248 [21]3 years ago
3 0

Answer:

1331.84 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement = 490 km

a = Acceleration

g = Acceleration due to gravity = 1.81 m/s² = a

From equation of linear motion

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -1.81\times 490000}\\\Rightarrow u=1331.84\ m/s

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km

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A 66-kg fellow stands on a digital scale in an elevator that accelerates upwards from rest to 4.5 m/s in 2.00 s. show answer Inc
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a tank circuit contains a capacitor and an inductor that produce 30 of reactance at the resonant frequency. the inductor has a q
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The total circuit current at the resonant frequency is 0.61 amps

What is a LC Circuit?

  • A capacitor and an inductor, denoted by the letters "C" and "L," respectively, make up an LC circuit, also referred to as a tank circuit, a tuned circuit, or a resonant circuit.
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Q =15 = (wL)/R

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R = 2 ohms

Zs = R + jXl = 2 +j30 ohms where Zs is the series LR impedance

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The impedance of the LC circuit is found from:

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Zp = (2+j30)(-j30)/(2 + j30-j30) = (900 -j60)2 = 450 -j30 = 451 < -3.81°

I capacitor = 277/-j30 = j9.23 amps

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To learn more about LC Circuit from the given link

brainly.com/question/29383434

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