The tissue that corresponds to this would be epithelial
Answer:
in dna their so adenine with thyamine &cytosine with guanine so in mitosis cells divides in two the they will finish the stage of telophase so they have 4 daughter cells I learn now gread 10
Hihi!
There are seven characteristics of living things: movement, breathing or respiration, excretion, growth, sensitivity, and reproduction! But sadly as for non-living things they lack most of these things. Their characteristics are that <span>they lack the </span>capability<span> for </span>growth<span>, </span>reproduction, respiration<span>, </span>metabolism<span>, and </span>movement<span>. They also cannot </span><span>respond to a stimuli and they also cannot</span><span> evolve and adapt to their environment. Isn't that kind of sad?
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I hope I helped!
-Jailbaitasmr
Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Francis Crick discovered the DNA structure.