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Phantasy [73]
3 years ago
6

How do you multiply fractions using cancellations

Mathematics
2 answers:
Serggg [28]3 years ago
7 0
Practically, if the nominator has a common factor with the denominator of the other fraction is can cancel out. For example. If u have the fractions 3/4 and 8/9, 3 and 9 have a common factor which is 3. So 3 goes into 9 3 times and 3 goes into 3, 1 time so the three becomes a 1 and the 9 becomes a 3. Same with the 4 and 8. They have a common factor of 4 (it can also be 2) 4 goes into4 one time (think of is a division), 4 divided by 4 is 1, 8 divided by 4 is two. So 4 goes into 8 2 times. So now it’d be easier to multiply. So it’d be 1/1 x 2/3 so now u just multiply across which would just equal 2/3.
Tcecarenko [31]3 years ago
5 0
<h3><u><em>When adding or subtracting fractions, the process is different depending on whether the denominators are the same or different. However, when multiplying or even dividing fractions, this is no longer a concern. Instead, you multiply the two numbers in the numerators and multiply the two numbers in the denominators. To save work later, always remember to check if you can cross-cancel</em></u></h3>
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Answer:

More than half

Step-by-step explanation:

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2 years ago
Please answer all parts of the question and all work shown.
faust18 [17]

Answer:

a. 0.4931

b. 0.2695

Step-by-step explanation:

Given

Let BG represents Boston Globe

NYT represents New York Times

P(BG) = 0.55

P(BG') = 1 - 0.55 = 0.45

P(NYT) = 0.6

P(NYT') = 1 -0.6 = 0.4

Number of headlines = 5

Number of depressed articles = 3 (at most)

a.

Let P(Read) = Probability that he reads the news the first day

P(Read) = P(He reads BG) and P(He reads NYT)

For the professor to read BG, then there must be at most 3 depressing news

i.e P(0) + P(1) + P(2) + P(3)

But P(0) + P(1) + .... + P(5) = 1 (this is the sample space)

So,

P(0) + P(1) + P(2) + P(3) = 1 - P(4) - P(5)

P(4) or P(BG = 4) is given as the binomial below

(BG + BG')^n where n = 5, r = 4

So, P(BG = 4) = C(5,4) * 0.55⁴ * 0.45¹

P(BG = 5). = (BG + BG')^n where n = 5, r = 5

So, P(BG = 5) = C(5,5) * 0.55^5 * 0.45°

P(0) + P(1) + P(2) + P(3)= 1 - P(BG = 4) - P(BG = 5)

P(0) + P(1) + P(2) + P(3) = 1 - C(5,4) * 0.55⁴ * 0.45¹ - C(5,5) * 0.55^5 * 0.45°

P(0) + P(1) + P(2) + P(3) = 0.7438

For the professor to read NYT, then there must be at most 3 depressing news

i.e P(0) + P(1) + P(2) + P(3)

But P(0) + P(1) + .... + P(5) = 1 (this is the sample space)

So,

P(0) + P(1) + P(2) + P(3) = 1 - P(4) - P(5)

P(4) or P(NYT = 4) is given as the binomial below

(NYT+ NYT')^n where n = 5, r = 4

So, P(NYT = 4) = C(5,4) * 0.6⁴ * 0.4¹

P(NYT = 5). = (NYT + NYT')^n where n = 5, r = 5

So, P(NYT = 5) = C(5,5) * 0.6^5 * 0.4°

P(0) + P(1) + P(2) + P(3)= 1 - P(NYT = 4) - P(NYT = 5)

P(0) + P(1) + P(2) + P(3) = 1 - C(5,4) * 0.6⁴ * 0.4¹ - C(5,5) * 0.6^5 * 0.4°

P(0) + P(1) + P(2) + P(3) = 0.6630

P(Read) = P(He reads BG) and P(He reads NYT)

P(Read) = 0.7438 * 0.6630

P(Read) = 0.4931

b.

Given

n = Number of week = 7

P(Read) = 0.4931

R(Read') = 1 - 0.4931 =

He needs to read at least half the time means he reads for 4 days a week

So,

P(Well-informed) = (Read + Read')^n where n = 7, r = 4

P(Well-informed) = C(7,4) * (0.4931)⁴ * (1-0.4931)³ = 0.2695

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Step-by-step explanation:

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d^2=12^2+10^2

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d^2=244

d=√244, since d=2r, r=d/2

r=√(244/4)

r=√61

The equation of a circle is (x-h)^2+(y-k)^2=r^2.  We found earlier that the center was at (-2,-4) and we just saw that r^2=61 so:

(x+2)^2+(y+4)^2=61
5 0
3 years ago
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