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tensa zangetsu [6.8K]
2 years ago
14

I need help plss its hard for me pls help and show the WORK plsss

Mathematics
1 answer:
My name is Ann [436]2 years ago
8 0
Is there a picture of the question?
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If the function f (x) has a domain of (a,b] and a range of [c,d), then what is the domain and range of g (x) = m × f (x) + n?
xz_007 [3.2K]
<h3>Answer: Choice A</h3>

Domain = (a,b]

Range = [mc + n,md + n)

==============================================

Explanation:

The domain stays the same because we still have to go through f(x) as our first hurdle in order to get g(x).

Think of it like having 2 doors. The first door is f(x) and the second is g(x). The fact g(x) is dependent on f(x) means that whatever input restrictions are on f, also apply on g as well. So going back to the "2 doors" example, we could have a problem like trying to move a piece of furniture through them and we'd have to be concerned about the f(x) door.

-------------------

The range will be different however. The smallest value in the range of f(x) is y = c as it is the left endpoint. So the smallest f(x) can be is c. This means the smallest g(x) can be is...

g(x) = m*f(x) + n

g(x) = m*c + n

All we're doing is replacing f with c.

So that means mc+n is the starting point of the range for g(x).

The ending point of the range is md+n for similar reasons. Instead of 'c', we're dealing with 'd' this time. The curved parenthesis says we don't actually include this value in the range. A square bracket means include that value.

6 0
2 years ago
What does one third equal
monitta
Divide \frac{1}{3}. 1÷3=0.33333333333333 \frac{1}{3} equals 0.333333333333333
5 0
3 years ago
Find the radius of the congruent circles. Thanks and hope you have a good rest of your day!!
Daniel [21]

Answer:

the radius is 10 since 10 plus ten is 20

8 0
3 years ago
I’ll give you brainlest if you answer this correctly
BaLLatris [955]
No give it to now lol
4 0
2 years ago
Read 2 more answers
If 6x=9y find the value of x:y.​
Ad libitum [116K]

Answer:

A complete angle is one which measures 360∘360∘.

The three angles

6x+20∘,9y+30∘,3z+40∘6x+20∘,9y+30∘,3z+40∘

add up to 360∘360∘, as per the question.

6x+20∘+9y+30∘+3z+40∘=360∘6x+20∘+9y+30∘+3z+40∘=360∘

⟹3(2x+3y+z)+90∘=360∘⟹3(2x+3y+z)+90∘=360∘

⟹3(2x+3y+z)=270∘⟹3(2x+3y+z)=270∘

⟹2x+3y+z=90∘⟹2x+3y+z=90∘

This is the required relation.

7 0
2 years ago
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