Answer:
third angle = (-6x + 161)°
Step-by-step explanation:
180° = (x)° + (5x + 19)° + third angle →
180° = (6x + 19)° + third angle →
180° – (6x + 19)° = (6x + 19)° + third angle – (6x + 19)° →
180° – (6x + 19)° = third angle →
180° + -(6x + 19)° = third angle →
180° + (-6x)° + (-19)° = third angle
180° – 6x° – 19° = third angle
(180° – 19°) – 6x° = third angle
161° – 6x° = third angle
third angle = 161 – 6x°
third angle = -6x° + 161°
third angle = (-6x + 161)°
The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign
4 + 6 = 10
10/2 = 5
Add 5 to -4
5 + -4 = 1
H is your midpoint
True. As long as AB and BC are on the same line, AB + BC = AC
hope this helps
X+4=2x+5
-1=x
hope this helps
Answer:
The fifth degree Taylor polynomial of g(x) is increasing around x=-1
Step-by-step explanation:
Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

and when you do its derivative:
1) the constant term renders zero,
2) the following term (term of order 1, the linear term) renders:
since the derivative of (x+1) is one,
3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero
Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is:
as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1
Answer:
9
Step-by-step explanation:
here you go!