<span>15-h)*h=40
15h-h^2=40
h^2-15h+40=0
solve for h by quadratic formula:
a=1, b=-15, c=20
ans:
h=3.47 or 11.53 cm (height)
b=15-h=11.53 or 3.47 cm (base)</span>
Answer:
y = 3x + 5
Step-by-step explanation:
Two lines which are parallel have the same gradient. This means that the parallel line must have a gradient of 3x
y = 3x + c
To figure out c you substitute in the given coordinate for the x and y values
8 = 3(1) + c
c = 5
y = 3x + 5
It's a simultaneous equation:
Steps:
1.Number the equations..
a+b=77 -1
a-b=13 -2
2. Choose what variable you want to use. In this case I would use the "b". Since the signs in front of the "b's" are different, add the two equations together
a + b = 77
+ + +
a (-b) = 13
Which gives;
2a = 90
Then solve to find a:
2a=90
a= 90/2
a=45
3.Then plug the "a" value into any of the original equations to find the "b" value. I would use equation 1 since the all the variables are positive.
a + b = 77
(45) + b = 77
b=77-45
b=32
4.Solution
a=45
b=32
"r < 3 or r > 2" is the one among the following choices given in the question that <span>could have resulted in this solution set. The correct option among all the options that are given in the question is the fourth option or option "d". I hope that this is the answer that has actually come to your desired help.</span>
