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4 years ago

Which function has the largest amplitude?

Mathematics

1 answer:

frutty [35]4 years ago

4 0

<h3>Answer: Choice A</h3>

The -3 out front of that function means |-3| = 3 is the amplitude, which is the largest of the four functions.

In general, the sine function is

y = A*sin(B(x-C)) + D

where |A| is the amplitude. In the first answer choice, A = -3 so |A| = |-3| = 3.

Cosine has the same format since cosine is just a phase shift of sine.

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If f(x) = 8x + 9, each time x increases by 1 unit, f(x) increases by<br> units.

alexira [117]

7 Units.

8(1)+9= 17
8(2)+9=25
8(3)+9=33

33-25=7. 25-17=7

3 0

3 years ago

A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s

Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

4 0

3 years ago

What decimal part of 80 is 90

Elodia [21]

88.89% of 90 would be 80

6 0

3 years ago

How to solve this ?<br>

beks73 [17]

Answer:

1350

Step-by-step explanation:

use binomial general term expression for (r+1)th term

get the power of x in terms of r.

equate the expression to -2 and solve for r.

replace value of r and calculate the coefficient.

5 0

1 year ago

Which graphs represent functions with the following key features?

Naddika [18.5K]

Answer:

Graph U

Step-by-step explanation:

A graph is used to illustrate the relationship between variables.

For graph U:

Graph U is positive on (-∞, ∞). The graph also increases on (-∞, ∞). The graph approaches 0 as x approaches -∞.

For graph V:

Graph V is positive on (-∞, ∞). The graph also increases on (-∞, ∞). The graph is negative as x approaches -∞.

For graph W:

Graph W is positive on (-∞, 0). The graph also increases on (-∞, 0). The graph approaches 0 as x approaches -∞.

For graph X:

Graph X is positive on (-∞, ∞). The graph also increases on (-∞, ∞). The graph is negative as x approaches -∞

For graph Y:

Graph Y is positive on (-∞, ∞). The graph also decreases on (-∞, ∞). The graph approaches 0 as x approaches ∞.

For graph Z:

Graph Z is negative on (-∞, ∞). The graph also decreases on (-∞, ∞). The graph is approaches 0 as x approaches -∞

8 0

3 years ago