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Lady_Fox [76]
2 years ago
15

List the numbers in order from least to greatest. −3, 9, −12, −7, 5, 1

Mathematics
1 answer:
musickatia [10]2 years ago
3 0

Answer:

-12, -7, -3, 1, 5, 9

Step-by-step explanation:

hope this helps

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In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
3 years ago
What's the probability of the compound event for. A bag contains 4 red, 8 blue, 6 yellow and 2 green marbles. Maria selects a ma
Nataly [62]

Given:

Number of red marbles = 4

Number of blue marbles = 8

Number of yellow marbles = 6

Number of green marbles = 2

To find:

The probability of getting a blue marble then a red marble, i.e., P(blue, red).

Solution:

Using the given information,

The total number of marbles = 4+8+6+2

                                                = 20

Probability of getting a blue marble in first draw is

P(Blue)=\dfrac{\text{Number of blue marbles}}{\text{Total number of marbles}}

P(Blue)=\dfrac{8}{20}

P(Blue)=\dfrac{2}{5}

Maria selects a marble, puts it back and then selects a second marble. It means the total number of marbles remains the same.

P(red)=\dfrac{\text{Number of red marbles}}{\text{Total number of marbles}}

P(red)=\dfrac{4}{20}

P(red)=\dfrac{1}{5}

Now, the probability of getting a blue marble then a red marble is

P(blue,red)=\dfrac{2}{5}\times \dfrac{1}{5}

P(blue,red)=\dfrac{2}{25}

Therefore, the required probability P(blue, red) is \dfrac{2}{25}.

5 0
3 years ago
Pls help everyone plssssssss
Yuri [45]

Answer:

A

Step-by-step explanation:

You divide the 2 and 8 to get your proportion.

8 0
2 years ago
A paint machine dispenses dye into paint cans to create different shades of paint. The amount of dye dispensed into a can is kno
Ket [755]

Answer:

0.9115 is the proportion of paint cans that contain less than 5.54 ml of the dye.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5 ml

Standard Deviation, σ = 0.4 ml

We are given that the distribution of amount of dye dispensed is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(paint cans contain less than 5.54 ml of the dye)

P( x < 5.54) = P( z < \displaystyle\frac{5.54 - 5}{0.4}) = P(z < 1.35)

Calculation the value from standard normal z table, we have,  

P(x < 5.54) =0.9115 = 91.15\%

0.9115 is the proportion of paint cans that contain less than 5.54 ml of the dye.

5 0
3 years ago
Which statement must be true to be able to use the AAS Congruence Theorem to prove triangle LMN is congruent to triangle PON?
aev [14]

Answer:

a

Step-by-step explanation:

2 angles. 1 sude

8 0
3 years ago
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