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Setler [38]
3 years ago
10

Juliet conducted a survey to find the favorite type of book of the students at her school. She asked 20 students from her class

what their favorite type of book is. Juliet concludes that short stories is the favorite type of book of the students in her school because 80% of the students in her class like short stories. Use at least two sentences to explain why Juliet's sample may not be valid. Make sure to use facts to support your answer.
Mathematics
1 answer:
pantera1 [17]3 years ago
3 0
The reason is because she didn't survey the school, but only surveyed her class, and to add to that It didn't say it was a random selection of students.

Juliet concludes that short stories is the favorite type of book of the students in her school because 80% of the students in her class like short stories.

That is inaccurate, she is assuming, that just because the students in her class chose short stories, she assumes the rest of the students will chose it.

Hope this helps! xx
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Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor
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Answer:

a) 0.0167

b) 0

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Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) Standard deviation of 23 bags

\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)

= 1 - P(z < 12.57)

Calculation the value from standard normal z table, we have,  

P(x < 5.95) = 1 - 1 = 0

c) P( fill volume of 23 bags is below 6 ounces)  = 0.001

P(x < 6)  = 0.001

P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})

Calculation the value from standard normal z table, we have,  

P( z \leq -3.09) = 0.001

\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

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Answer:

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Answer:

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