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3 years ago

Please help on these two

Mathematics

1 answer:

jeyben [28]3 years ago

8 0

Answer:

For your first problem you want to see what all the sides would equal

You would have to combine them all into one big equation

5x-7+3x+1+4x=30 (now you want to combine like terms)

12x-7+1=30 (combined the x's together)

12x-6=30 (added -7 and 1)

12x=36 (added 6 to each side)

x=3 (divided 12 to each side)

Now you wanna plug 4 in for x for each side to find out the largest to smallest

AB=5(3)-7= 8

BC=3(3)+1= 10

AC=4(3)= 12

So in order from smallest to largest would be angle C, B, A because

Angle C is the smallest angle because the sides AC and BC are the longest so they form the smallest angle

Then it would be angle A being the largest because the smallest sides in length AB and BC make up the biggest angle

The next problem would be that in order for it to have to be a triangle the two smallest sides needs to add up higher than the third side so

11, 11, 24, 11+11=22, which is less than 24 so not this one

18,12,9, 9+12=21 which is greater that 18 so this one would be a triangle

9,10,19, 9+10=19 which 19 isn't greater than 19 so this one is not a triangle

4,7,23, 4+7=11 which is less than 23, so this one is also not a triangle

So your answer would be 18cm,12cm,9cm

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Is 5/5 x 13 more than or less than 13?

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Answer:Its equal

Step-by-step explanation:5 /5 (13) =(1)(13) =13

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Oman said that it is impossible to raise a number to the power of 2 and get a value less than the original number. Do you agree

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3 years ago

The Science Club went on a two-day field trip. The first day the members paid $60 for transportation plus $11 per ticket to the

sattari [20]

Answer:

145 + 19t

Step-by-step explanation:

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3 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

2 years ago

Simplify:0.3(x-2y)+0.5x-y

astraxan [27]

Answer:

0.3[x-2y] + 0.5x - y

Use the distributive property: a(b-c) = ab - ac

0.3x - 0.6y + 0.5x - y

Now, add/subtract all like terms

0.3x + 0.5x - 0.6y - y

0.8x - 1.6y

If you want, we can simplify that down further to:

0.8(x - 2y)

7 0

3 years ago

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Please help on these two​

Please help on these two