Answer:
Option c (byte alignment) is the appropriate alternative.
Explanation:
- This same alignment problem emerges if another architecture does seem to be an application-specific byte, however, the design phrase set education seems to be greater within one byte. In these kinds of case scenarios, because when recovering a significance from people's memories the structure can come back less than half including its bits.
- If memory access isn't synchronized, it seems to have been unevenly spaced. Recognize that even by interpretation, byte storage access has always been connected.
Some other choices aren't connected to the type of situation in question. So the above is the right option.
To observe ultraviolet, x-rays, gamma-rays or infrared, astronomers have had to put telescopes outside of Earth's atmosphere, normally in orbit around the Earth.
Answer:
A ) Sizeof(arr)/sizeof(arr[0])
B) Sizeof(arr[0])/sizeof(arr[0][0])
C) Sizeof(arr[0][0])/Sizeof(arr[0][0][0])
D) Sizeof(arr[0][0][0])/Sizeof(int)
Explanation:
using only the size of operator and the name of the array to write an expression that will yield each of the array Dimensions in left-to-right order
A ) Sizeof(arr)/sizeof(arr[0])
B) Sizeof(arr[0])/sizeof(arr[0][0])
C) Sizeof(arr[0][0])/Sizeof(arr[0][0][0])
D) Sizeof(arr[0][0][0])/Sizeof(int)
attached below is the handwritten copy
Answer:
Question1:
day = int(input("Enter in Numeric Today's day:"))
if (x == 15 or x == 30):
print("You have a payday today!")
if (x != 15 and x != 30):
print("Its is not certainly a payday today but dont feel bad.")
Question 2:
red = int(input("Enter the value for red: "))
green = int(input("Enter the value for green: "))
blue = int(input("Enter the value for blue: "))
if (red > 255 or red < 0):
print("The value of Red is not correct.")
if (green > 255 or green < 0):
print("The value of Green is not correct.")
if (blue > 255 or blue < 0):
print("The value of Blue is not correct.")
Explanation:
Please check the answer section.
