Answer:
Network security
Explanation:
Network security is a category of cybersecurity that is related to the protection of the infrastructure of the computer network from unauthorized access and intrusion that may be from intended attack or from an expedient program which may result in the modification, malfunctioning, misuse or unacceptable disclosure of the network and the contents of the network
The category of cybersecurity that 'prevents intruders from accessing, misusing, destroying, adapting, or improperly disclosing networks, network infrastructure, or the information contained within networks' is network security.
Answer:
year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print(str(year) + " - leap year")
else:
print(str(year) +" - not a leap year")
else:
print(str(year) + " - leap year")
else:
print(str(year) + "- not a leap year")
Explanation:
*The code is in Python.
Ask the user to enter a year
Check if the <u>year mod 4</u> is 0 or not. If it is not 0, then the year is not a leap year. If it is 0 and if the <u>year mod 100</u> is not 0, then the year is a leap year. If the <u>year mod 100</u> is 0, also check if the <u>year mod 400</u> is 0 or not. If it is 0, then the year is a leap year. Otherwise, the year is not a leap year.
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
</span>
As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
Answer:
-The correct width and height must be input into the pixelation widget to produce the image.
- The fact that only 32 bits were used to represent the image indicates relatively large sample squares were used. The digital image may vary from the analog image significantly.
Explanation:
Answer:
I do believe that it is a grammar mistake.
