W - 5,129 = 2,329 A. w = 7,468 B. w = 7,558 C. w = 7,458

HELP ASAP!!

olga2289 [7]

Answer:

62.5%

Step-by-step explanation:

150/240=0.625

you do 0.625x100 to get the percent.

8 0

2 years ago

Can you help me with my Math, please?

creativ13 [48]

The first poster is not an accurate representation of the painting, but the second poster is an accurate representation because the ratio between the first and original lengths did not equal the ratio between the first and original widths but the second poster's ratios were equal.

6 0

3 years ago

Read 2 more answers

A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January

Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that $p = 0.23$

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789$

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084$

$P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181$

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343$

$P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225$

$P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439$

$P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109$

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116$

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

$E(X) = np = 10*0.23 = 2.3$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33$

The expected number is 2.3 and the standard deviation is 1.33.

5 0

3 years ago

your planning to build a boat. you have a sample board of wood that you want to use . the board has an area of 1/3 ft squared an

frosja888 [35]

Given:
Area of sample board: 1/3 square ft.
Weight of sample board: 1/5 lbs

We need to get the weight of the whole square foot.

1/3 square foot is only a part of the whole square foot. Its corresponding weight is 1/5 pounds. We need to divide the area by its corresponding weight to get the total weight per square foot.

1/3 ÷ 1/5

Rules of dividing fractions:
1st fraction: 1/3 ; 2nd fraction: 1/5

1) Get the reciprocal of the 2nd fraction. 1/5 ⇒ 5/1

2) Multiply 1st fraction to the reciprocal of the 2nd fraction
1/3 * 5/1 = 5/3

3) Simplify fraction.
5/3 is an improper fraction. To simplify it, it needs to become a mixed fraction.

5/3 = 1 2/3 pounds.

8 0

3 years ago

99 POINT QUESTION PLUS BRAINLIEST!!!

Katyanochek1 [597]

Yay, I like das stuff

I think I learned the washer method
goes like this

$area=\pi \int\limits^a_b {(outercurve)^2-(innercurve)^2} \, dx$

ok, so

actuallly, this is easier

y=49-x^2 and
y=0
see when they intersect again
they intersect at -7 and 7
if we do integrate from -7 to 7, then it wil give 0 (because integration is area under the curve), so note that they are same both sides so integrate from 0 to 7 then double the volume to get both sides
so it can't be C or D
It also can'nt be A because it should not be multipied by 4, it should be multipied by 2

basically, we don't need the washer method
remember, area=pir^2
the disk method then
we are summing up all the radii disks and squareing them
but doubleing them so
$area=2\pi (\int\limits^7_0 {49-x^2} \, dx )^2$
no idea why we need the inside part to be x(49-x^2), that is intersting

6 0

3 years ago

W - 5,129 = 2,329A. w = 7,468B. w = 7,558C. w = 7,458