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rusak2 [61]
2 years ago
12

Sarita bought an MP3 player on sale for 30% off the regular price. Sarita also had a coupon which offered an additional $10.00 o

ff the sale price. If the regular price of the MP3 player was $75.00, what was the final sale price of the MP3 player before tax? $52.50 O $22.50 KA 0 $45.50 O $42.50 1 2 3 4 5 6 7 8 9 10 Next Sign out 0 US​
Mathematics
1 answer:
Anna [14]2 years ago
8 0

Answer:

$42.50

Step-by-step explanation:

First, we can take the 30% sale into account. We can start by converting 30% into a decimal by dividing it by 100: 30/100 = 0.3. Then, we can multiply that by the original price, 75, to get 75 * 0.3 = 22.5 as the amount given off due to the sale. We can subtract this from 75 to get our sale price of 75 - 22.5 = 52.5. Next, we can utilize the other coupon to get an additional $10 off, so we can subtract that from the original sale price to get the final sale price of

52.5 - 10 = 42.5

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Sveta_85 [38]

Answer:

(4, 80) Which is L

Step-by-step explanation:

First number should be on the X axis and the second on the Y axis.

6 0
3 years ago
Solve for n.<br> n^2–15n–16=0
Fofino [41]
N =  {15   +-  root of ( 225 + 64)  } / 2
  =  {15  +-  root of 289  } / 24
  = 15 + 17 } / 2   or  { 15 -17 } /2 
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5 0
3 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
What is 8/12 + A/12=2/b
il63 [147K]

Answer:

the answer i got was a=−8b+24/b

Step-by-step explanation:

hoped I helped:)

8 0
3 years ago
What is the measure of the angle at the tail end of the kite? if the top area is where its pointed is 122?
nataly862011 [7]

Answer:

The angle is 58 degrees

Step-by-step explanation:

Given

See attachment for kite

Required

The angle at the tail end

Represent this angle with x.

From the attached kite, we have:

1 angle = 122

2 angles = right-angled

So, we have:

x + 122 +90+90 = 360 --- sum of angles in a kite

x + 302 = 360

Solve for x

x =- 302 + 360

x =58^\circ

8 0
3 years ago
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