Sarita bought an MP3 player on sale for 30% off the regular price. Sarita also had a coupon which offered an additional $10.00 o
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Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is
, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
To solve the problem we must know about quadratic equations.
<h2>Quadratic Equation</h2>A quadratic equation is an equation that can be written in the form of
ax²+bx+c.
Where a is the leading coefficient, and
c is the constant.
The breadth of the rectangle is 200 ft, while the length is 210 ft.
<h2>Explanation</h2>Given to us
- Area of the parking lot = 42,000 ft²
- Perimeter of the parking lot = 820 ft
Area of the parking lot = Area of the rectangle
42,000 ft² = Length x Breadth
Solving for L,
Perimeter of the parking lot = Perimeter of the rectangle
820 ft. = 2(Length + Breadth)
820 ft. = 2(L+ B)
Substituting the value of L,
Solving the quadratic Expression,
Equation the factors against zero,
B-210=0
B = 210
B-200=0
B = 200
Hence, the breadth of the rectangle is 200ft, while the length is 210 ft.
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