Question

How many moles of NH3 are necessary to produce 0.824 mol N2

Answer 1

Answer:

1.648 moles of ammonia will be required to produce 0.824 moles of nitrogen gas.

Explanation:

$2NH_3\rightarrow N_2+3H_2$

According to reaction 1 mole of nitrogen gas is produced by 2 moles of ammonia.

Then, 0.824 moles of nitrogen gas will be produced by:

$\frac{2}{1}\times 0.824 mol=1.648 mol$

1.648 moles of ammonia will be required to produce 0.824 moles of nitrogen gas.

Answer 2

Moles H2 required = 3 x 0.230=0.690 
moles H2 in excess = 0.750 -0.690 =0.060 

the ratio between N2 and NH3 is 1 : 2 
moles NH3 = 0.230 x 2 = 0.460