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Fantom [35]
3 years ago
7

If 4.20 mol Al was mixed with 1.75 mol Fe2 O3 which reactant is the limiting reactant?

Chemistry
1 answer:
Dafna11 [192]3 years ago
7 0
4.20 mol Al would react completely with 4.20 x (1/2) = 2.10 mol Fe2O3, but there is not that much Fe2O3 present, so Fe2O3 is the limiting reactant. (1.75 mol Fe2O3) x (2/1) x ( 55.8452 g Fe/mol) = 195 g Fe 3 MgO + 2 H3PO4 → Mg3(PO4)2 + 3 H2O (15.0 g MgO) / (40.3045 g MgO/mol) = 0.37217 mol MgO (18.5 g H3PO4) / (97.9953 g H3PO4/mol) = 0.18878 mol H3PO4 0.18878 mol H3PO4 would react completely with 0.18878 x (3/2) = 0.28317 mole of MgO, but there is more MgO present than that, so MgO is in excess and H3PO4 is the limiting reactant. Now we must consider why the problem tells us "17.6g of Mg3(PO4)2 is obtained". The first possibility is that it's just there for the sake of confusion -- in which case ignore it and proceed this way: ((0.37217 mol MgO initially) - (0.28317 mole MgO reacted)) x (40.3045 g MgO/mol) = 3.59 g MgO left over However, if the amount of magnesium phosphate obtained is given because the reaction was stopped before it was complete, the amount obtained governs the amount reacted and the amount left over, so proceed this way: (17.6g Mg3(PO4)2) / (262.8581 g Mg3(PO4)2/mol) x (3/1) = 0.20087 mol MgO reacted ((0.37217 mol MgO initially) - (0.20087 mole MgO reacted)) x (40.3045 g MgO/mol) = 6.90 MgO left over
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2 and a half
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so your answer is
2 and a half
5 0
3 years ago
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6 0
3 years ago
The 85.2-g sample of the compound x4o10 contains 48.0 g of oxygen atoms. what is the molar mass of element x?
Vedmedyk [2.9K]
X4O10
Let molar mass of X be y
molar mass =  4y + 10 x 16 = 4y+160

so, moles = 85.2 / (4y+160)

Moles of oxygen = 10 x [85.2 / (4y+160) ]
Mass of oxygen  = 16 x 10 x [85.2 / (4y+160) ]
which is 48.0

so, 48 = 16 x 10 x [85.2 / (4y+160) ]

Solve the equation to get y.

y = 31
5 0
2 years ago
What is the molarity of a solution that contains 0.400 mol HCI in 9.79 L solutions ​
USPshnik [31]

Molarity's formula is known as: Molarity(M)=moles of solute/liters solution.

In this case we are already given moles and liters so you just have to plug the numbers into the equation.

0.400 mol HCL/9.79L solution=0.040858M

If you were to use scientific notation, the answer will be: 4.1*10^-2, but otherwise, you can just use the decimals above and round appropriately as you see fit.

6 0
3 years ago
Antacids work to relieve stomach acids because of which of the following types of reactions?
Anastaziya [24]

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Decomposition is a type of chemical reaction in which larger compound breaks down into two or more smaller compounds.

AB\rightarrow A+B

Double displacement reactions is defined as the chemical reaction in which exchange of ions takes place.

AB+CD\rightarrow AD+CB

Synthesis reaction is a type of reaction in which two or more smaller compounds combines to form a single large compound.

A+B\rightarrow AB

Single displacement reaction is a type of reaction in which a more reactive metal displaces a less reactive metal from its chemical reaction.

A+BC\rightarrow AC+B

In stomach, an acid is present known as hydrochloric acid and to neutralize its effect, antacid is taken which has CaCO_ as a component.

The reaction between HCl and CaCO_3 is a type of neutralization reaction and it is a type of double displacement reaction.

The equation between the two follows:

CaCO_3+HCl\rightarrow CaCl_2+H_2O+CO_2

Hence, the correct answer is Option B.

4 0
2 years ago
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