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lord [1]
3 years ago
15

Which expression is equivalent to (x27y)^1/3

Mathematics
2 answers:
grin007 [14]3 years ago
8 0

Answer:

(x^{9}y^\frac{1}{3})

or

(x^{9}\sqrt[3]{y})

Step-by-step explanation:

Given in the question an expression

(x^{27}y )^\frac{1}{3}

We will apply the power rule

The "power rule" tells us that to raise a power to a power, just multiply the exponents.

(x^{27*\frac{1}{3} }y^\frac{1}{3})

(x^{9}y^\frac{1}{3})

As we know that

x^{1/n} = \sqrt[n]{x}

so we can write the above expression as

(x^{9}\sqrt[3]{y})

SVETLANKA909090 [29]3 years ago
4 0

Answer:

3∛(xy)

Step-by-step explanation:

(x27y)^1/3

Simplified form will be 3/x³y³

Because;

27^(1/3) = 3

x^(1/3) = ∛x

y^(1/3) = ∛y

Which gives us 3∛(xy)

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Zoey has 99 years .She plans to make 5 bangles .Each bangle is made using 30 beads how many more beads does zoey need?​
drek231 [11]

Note: I am assuming you meant to say:

  • Zoey has 99 beads instead of 99 years.

Answer:

Zoey needs 51 more beads to make 5 bangles.

Step-by-step explanation:

Total number of beads Zoey currently has = 99 beads

Beads need to make one bangel = 30 beads

so

Beads need to make 5 bangles = 30 × 5 = 150 beads

Since she has already 99 beads.

So, all we need s to subtract 99 beads from 150 beads.

Therefore,

The number of beads Zoey needs = 150 - 99

                                                          = 51 beads

Thus, Zoey needs 51 more beads to make 5 bangles.

4 0
3 years ago
bianca is building a sandbox that will hold 4 cubic yards of sand. she wants it to be 18 inches deep and 2 yards wide. what will
tamaranim1 [39]
Length should be 2/5yd:

18inch*1yd/36inch=.5yd=> depth

volume= 2(length*width+lenght*depth+depth*width)

let l to be the length.

volume= 2(l*2+2(.5)+.5*2)

volume=5l+2

4=5l+2

2=5l

l=2/5


5 0
3 years ago
A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa
yarga [219]

Answer:

z= \frac{85-70}{10}=1.5

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

E(X)= \mu =70, SD_X=\sigma=10  

The z score is given by:

z=\frac{x-\mu}{\sigma}

If we use this we got:

z= \frac{85-70}{10}=1.5

Let Y the random variable that represent the scores for his friend, and for this case we know that:

E(Y)= \mu =35, SD_Y=\sigma=5  

The z score is given by:

z=\frac{y-\mu}{\sigma}

If we use this we got:

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

3 0
3 years ago
Find real solutions x-(4-8x)^0.5=0
Vadim26 [7]

Answer:

There are no real roots for this equation.

Step-by-step explanation:

The only solution is irrational: x-√(4-8x)=0

I have provided a graph to help you with this problem.

Hope this helps! :)

5 0
3 years ago
Problem #2 A, B,C,D,E
PilotLPTM [1.2K]

2x+4

2(x+4)

(x/5)+6

(x+6)squared

X-5/x

4 0
3 years ago
Read 2 more answers
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