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4 years ago

6

Plz help.... Carlos is working on a personal net worth statement for his family. Which of the following is not considered a liab

ility: student loan, car loan, medical bills, or child care costs

1 answer:

larisa86 [58]4 years ago

3 0

Student loan is something thats not considered one

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F(-3)=2xsquard root of 2 +9

kipiarov [429]

Solution = 2(-3)^2 + 9
= 18 + 9
= 27

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4 years ago

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Here are scores for two softball teams for seven innings. Rosie's Riveters beat The Susan Bees by how many runs?

Rashid [163]

13-10=3, they won by 3 runs.

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3 years ago

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Help ASAP please thanks

andrew-mc [135]

Answer:

#1: -2 ≤ y ≤ ∞

#2: -2 ≤ x ≤ 2

#3: -4 ≤ y ≤ 3

#4: -5 ≤ y ≤ ∞

#5: 0 ≤ x ≤ ∞

Step-by-step explanation:

To do these, you must understand what range and domain are:

Range: all the values that y can be

Domain: all the values that x can be

#1: It's asking for range, so look at the posible y values. The smallest y value is -2, and the largest is actually infinity. So, the range is: -2 ≤ y ≤ ∞.

#2: It's asking for domain, so look at the possible x values. The smallest is -2 and the largest is 2, so: -2 ≤ x ≤ 2.

#3: Again, it's asking for range, so look at the possible y values. The smallest is -4, and the largest is 3, so: -4 ≤ y ≤ 3.

#4: It's asking for range. The smallest value is -5, and the largest goes to infinity (from the arrows), so: -5 ≤ y ≤ ∞.

#5: It's asking for domain. The smallest x value is 0, and it goes to infinity. So: 0 ≤ x ≤ ∞.

6 0

3 years ago

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The number 20 is no less than the difference of 4 times a number c and 8.

sammy [17]

Answer:

20 >= 4*c - 8

Step-by-step explanation:

5 0

3 years ago

When a scientist conducted a genetics experiments with peas, one sample of offspring consisted of 943 peas, with 717 of them hav

pshichka [43]

Using the normal approximation to the binomial distribution, it is found that:

a) 0.242 = 24.2% probability of getting 717 or more peas with red flowers.

b) Since Z < 2, 717 peas with red flowers is not significantly high.

c) Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

For each pea, there are only two possible outcomes. Either they have a red flower, or they do not. The probability of a pea having a red flower is independent of any other pea, which means that the binomial distribution is used to solve this question.

Binomial distribution:

Probability of x successes on n trials, with p probability.

Normal distribution:

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

If Z > 2, the result is considered <u>significantly high</u>.

If $np \geq 10$ and $n(1-p) \geq 10$ , the binomial distribution can be approximated to the normal with:

$\mu = np$

$\sigma = \sqrt{np(1-p)}$

In this problem:

943 peas, thus, $n = 943$
3/4 probability of being red, thus $p = \frac{3}{4} = 0.75$ .

Applying the approximation:

$\mu = np = 943(0.75) = 707.25$

$\sigma = \sqrt{np(1-p)} = \sqrt{943(0.75)(0.25)} = 13.297$

Item a:

Using continuity correction, this probability is $P(X \geq 717 - 0.5) = P(X \geq 716.5)$ , which is <u>1 subtracted by the p-value of Z when X = 716.5</u>.

Then:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{716.5 - 707.25}{13.297}$

$Z = 0.7$

$Z = 0.7$ has a p-value of 0.758.

1 - 0.758 = 0.242

0.242 = 24.2% probability of getting 717 or more peas with red flowers.

Item b:

Since Z < 2, 717 peas with red flowers is not significantly high.

Item c:

Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

A similar problem is given at brainly.com/question/25212369

6 0

3 years ago