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Anuta_ua [19.1K]

3 years ago

15

5(-3y+3z)-3(-5z-y) simplified

1 answer:

Virty [35]3 years ago

8 0

Answer:

5-(-3y+3z)-3(-5z-y) = 6y+12z+5

Step-by-step explanation:

5−(−3y+3z)−3(−5z−y)

Distribute:

=5+3y+−3z+(−3)(−5z)+(−3)(−y)

=5+3y+−3z+15z+3y

Combine Like Terms:

=5+3y+−3z+15z+3y

=(3y+3y)+(−3z+15z)+(5)

=6y+12z+5

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How do I find the inverse of this problem?

raketka [301]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Inverse of real function.

Let's consider here, g(n) = y ,

so we get as,

$y = \sqrt[3]{ \frac{n - 1}{2} }$

no, cubing the power both side we get as,

=>

${y}^{3} = \frac{n - 1}{2}$

now,

$2 {y}^{3} = n - 1$

so finally, we get as,

=>

$n = 2 {y}^{3} + 1$

hence,here, n = inverse of the g(n) function.

so,

g^-1 (n) = 2y^3+1.

7 0

2 years ago

Please help i am being timed i beg you please help

Viefleur [7K]

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6 0

2 years ago

Read 2 more answers

Han has 5 pencils and Andre has 8

Tatiana [17]

Answer:

That's all I could think that you might need. Finish your question please

Step-by-step explanation:

Together: 13

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4 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

Given the expression -7+6i/2+3i , perform the indicated operation and write the answer in the form a + bi.

Andre45 [30]

$\dfrac{-7+6i}{2+3i}\times\dfrac{2-3i}{2-3i}=\dfrac{(-7+6i)(2-3i)}{(2+3i)(2-3i)}=\dfrac{4+29i}{4-9i^2}=\dfrac4{13}+\dfrac{29}{13}i$

8 0

3 years ago