Hello!
Your answer is the second option.
Hope this helps!
Answer:
4 & 17/20
Step-by-step explanation:
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
After 10 weeks: 40 inches
Step-by-step explanation:
Equation
15 + 2.5w = h
15 = beginning height
2.5 = rate per week
w = weeks passed
h = total height
Answer:
x=-2
Step-by-step explanation:
Let's solve your equation step-by-step.
−6x=5x+22
Step 1: Subtract 5x from both sides.
−6x−5x=5x+22−5x
−11x=22
Step 2: Divide both sides by -11.
−11x
−11
=
22
−11
x=−2
