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lawyer [7]
3 years ago
14

A 2-column table with 4 rows. The first column is labeled x with entries negative 5, 1, 4, 6. The second column is labeled y wit

h entries 9, 0, negative 7, negative 1.
What is the range of the given function?

{x | x = –5, 1, 4, 6}
{y | y = –7, –1, 0, 9}
{x | x = –7, –5, –1, 0, 1, 4, 6, 9}
{y | y = –7, –5, –1, 0, 1, 4, 6, 9}
Mathematics
2 answers:
Inessa [10]3 years ago
5 0

Answer:

The answer to your question is: {y | y = –7, –1, 0, 9}

Step-by-step explanation:

Range is given by the dependent variable "y".

So, according to the information given, range must be 9,0, -7 and  -1

or -7, -1, 0 , 9.

The second option.

Sergeeva-Olga [200]3 years ago
4 0

Answer: {y | y = –7, –1, 0, 9}  

Step-by-step explanation:

We usually denote independent variable as x and dependent variable as y.

The range of a function is basically the set of all resulting y-values.

Given : The first column is labeled x with entries - 5, 1, 4, 6. The second column is labeled y with entries 9, 0,-7, -1.

Then, the  range of the given function = values in second columns

i.e. Range={y | y = –7, –1, 0, 9}  [Arranged in order]

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Assume the line of best fit for a data set is given by y=22x+32. What data points are predicted by the line of best fit? Check a
malfutka [58]
Hi. You have to do trial and error with each of the choices to see which of those apply. They are points on the given function y=22x+32 that lie on point (x,y). Just substitute the x-and y values to the function.

a. (10,480) => x = 10, y = 480
     y = 480 = 22(10) + 32
     480 = 252 (does not apply)

b. (5,142) => x = 5, y = 142
     y = 142= 22(5) + 32
     142 = 142 (apply)

c. (8,208) => x = 8, y = 208
     y = 208 = 22(8) + 32
     208 = 208 (apply)

d. (7,154) => x = 7, y = 154
     y = 154 = 22(7) + 32
     154 = 186 (does not apply)

The answer is B and C.
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3 years ago
The function {(-1, 2), (-2, 1), (0, 2)} has the function rule y = x + 3. HELPPPPPP
Komok [63]
Answer: True
Explanation: hope this help
7 0
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The Salk polio vaccine experiment in 1954 focused on the effectiveness of the vaccine in combating paralytic polio. Because it w
sdas [7]

Answer:

Step-by-step explanation:

Hello!

The variables of interest are:

X₁: Number of cases of polio observed in kids that received the placebo vaccine.

n₁= 201299 total children studied

x₁= 110 cases observed

X₂: Number of cases of polio observed in kids that received the experimental vaccine.

n₂= 200745 total children studied

x₂= 33 cases observed

These two variables have a binomial distribution. The parameters of interest, the ones to compare, are the population proportions: p₁ vs p₂

You have to test if the population proportions of children who contracted polio in both groups are different: p₂ ≠ p₁

a)

H₀: p₂ = p₁

H₁: p₂ ≠ p₁

α: 0.05

Z= \frac{(p'_2-p'_1)-(p_2-p_1)}{\sqrt{p'[\frac{1}{n_1} +\frac{1}{n_2} ]} }

Sample proportion placebo p'₁= x₁/n₁= 110/201299= 0.0005

Sample proportion vaccine p'₂= x₂/n₂= 33/200745= 0.0002

Pooled sample proportion p'= (x₁+x₂)/(n₁+n₂)= (110+33)/(201299+200745)= 0.0004

Z_{H_0}= \frac{(0.0002-0.0005)-0}{\sqrt{0.0004[\frac{1}{201299} +\frac{1}{200745} ]} }= -4.76

This test is two-tailed, using the critical value approach, you have to determine two critical values:

Z_{\alpha/2}= Z_{0.025}= -1.96

Z_{1-\alpha /2}= Z_{0.975}= 1.96

Then if Z_{H_0} ≤ -1.96 or if Z_{H_0} ≥ 1.96, the decision is to reject the null hypothesis.

If -1.96 < Z_{H_0} < 1.96, the decision is to not reject the null hypothesis.

⇒ Z_{H_0}= -4.76, the decision is to reject the null hypothesis.

b)

H₀: p₂ = p₁

H₁: p₂ ≠ p₁

α: 0.01

Z= \frac{(p'_2-p'_1)-(p_2-p_1)}{\sqrt{p'[\frac{1}{n_1} +\frac{1}{n_2} ]} }

The value of Z_{H_0}= -4.76 doesn't change, since we are working with the same samples.

The only thing that changes alongside with the level of significance is the rejection region:

Z_{\alpha /2}= Z_{0.005}= -2.576

Z_{1-\alpha /2}= Z_{0.995}= 2.576

Then if Z_{H_0} ≤ -2.576or if Z_{H_0} ≥ 2.576, the decision is to reject the null hypothesis.

If -2.576< Z_{H_0} < 2.576, the decision is to not reject the null hypothesis.

⇒ Z_{H_0}= -4.76, the decision is to reject the null hypothesis.

c)

Remember the level of significance (probability of committing type I error) is the probability of rejecting a true null hypothesis. This means that the smaller this value is, the fewer chances you have of discarding the true null hypothesis. But as you know, you cannot just reduce this value to zero because, the smaller α is, the bigger β (probability of committing type II error) becomes.

Rejecting the null hypothesis using different values of α means that there is a high chance that you reached a correct decision (rejecting a false null hypothesis)

I hope this helps!

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Answer:

A-2515.57647469

Step-by-step explanation:

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2 years ago
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Scorpion4ik [409]
We know that

The Euler's formula state that, the number of vertices, minus the number of edges, plus the number of faces, is equal to two

V - E + F = 2
clear F
F=2-V+E

in this problem
V=8
E=14
F=?
so
F=2-8+14
F=8

the answer is
8 faces
7 0
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