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lawyer [7]
3 years ago
14

A 2-column table with 4 rows. The first column is labeled x with entries negative 5, 1, 4, 6. The second column is labeled y wit

h entries 9, 0, negative 7, negative 1.
What is the range of the given function?

{x | x = –5, 1, 4, 6}
{y | y = –7, –1, 0, 9}
{x | x = –7, –5, –1, 0, 1, 4, 6, 9}
{y | y = –7, –5, –1, 0, 1, 4, 6, 9}
Mathematics
2 answers:
Inessa [10]3 years ago
5 0

Answer:

The answer to your question is: {y | y = –7, –1, 0, 9}

Step-by-step explanation:

Range is given by the dependent variable "y".

So, according to the information given, range must be 9,0, -7 and  -1

or -7, -1, 0 , 9.

The second option.

Sergeeva-Olga [200]3 years ago
4 0

Answer: {y | y = –7, –1, 0, 9}  

Step-by-step explanation:

We usually denote independent variable as x and dependent variable as y.

The range of a function is basically the set of all resulting y-values.

Given : The first column is labeled x with entries - 5, 1, 4, 6. The second column is labeled y with entries 9, 0,-7, -1.

Then, the  range of the given function = values in second columns

i.e. Range={y | y = –7, –1, 0, 9}  [Arranged in order]

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For what values of x is the expression below defined?<br> Look at the picture(15 points)
Leya [2.2K]

Answer:

D. -5 <= x < 1

Step-by-step explanation:

the values under the square-root radical must not be negative, AND

the value of the denominator must not be 0 or negative

x+5 >=0  or x >= -5

and 1-x > 0 or x < 1

So the answer is -5 <= x < 1

4 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e.  \mu=61 and \sigma=9

To find :  The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and 34+3(9).

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma). (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma) = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0
3 years ago
What is the following product?
Leona [35]

Answer:

First option: 6y^2sqrt(10) + 12sqrt(5y)

Step-by-step explanation:

3sqrt(10) * (2y^2 + 2sqrt(2y)

= 6y^2sqrt(10) + 6sqrt(20y)

= 6y^2sqrt(10) + 12sqrt(5y)

3 0
2 years ago
Which ordered pair is a solution to the inequality 3x - 4y &lt; 16 ?
fgiga [73]

Answer:

C.

Step-by-step explanation:

You are given 3x-4y<16 and we want to see which of the ordered pairs is a solution.

These ordered pairs are assumed to be in the form (x,y).

A. (0,-4) ?

3x-4y<16 with (x=0,y=-4)

3(0)-4(-4)<16

0+16<16

16<16 is not true so (0,-4) is not a solution of the given inequality.

B. (4,-1)?

3x-4y<16 with (x=4,y=-1)

3(4)-4(-1)<16

12+4<16

16<16 is not true so (4,-1) is not a solution of the given inequality.

C. (-3,-3)?

3x-4y<16 with (x=-3,y=-3)

3(-3)-4(-3)<16

-9+12<16

   3<16 is true so (-3,-3) is a solution to the given inequality.

D. (2,-3)?

3x-4y<16 with (x=2,y=-3)

3(2)-4(-3)<16

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18<16 is false so (2,-3) is not a solution to the given inequality.

4 0
3 years ago
Two and three fourths plu one and three eight
crimeas [40]
2 3/4 + 1 3/8 = 4.125 and there is your answer
6 0
3 years ago
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