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grigory [225]
3 years ago
7

Chaz is a college student. He has a checking account balance of. -$52.00. His roommate will,s checking account balance is -$59.2

5. Chaz thinks that will owes more to the bank than Chaz does. Is Chaz correct? Explain your answer.
Mathematics
1 answer:
Luda [366]3 years ago
3 0
Pretend you and Will owe a friend instead of the bank, pull out your wallets and pay your debts.  Who has to take out more money from their wallet?  Of course, Will has to take out $9.25 more than Chaz.
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Virty [35]

Answer:

B.6

Step-by-step explanation:

When we add and subtract, we do it from left to right

13+ (-12) - (-5)

13+-12

13-12 = 1

1 - -5

A negative negative is a positive

1 +5

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8 0
3 years ago
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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
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coldgirl [10]

Answer:

x = 7

Step-by-step explanation:

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7x \div 7 = 49 \div 7

x = 49 \div 7 = 7

\boxed{\green{x = 7}}

3 0
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patriot [66]

Answer:

The choice two;

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Step-by-step explanation:

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