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gregori [183]
3 years ago
11

Suppose A is a matrix and k is a positive integer. What does the notation Ak mean?

Mathematics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:

Scalar product

Step-by-step explanation:

The scalar product of a matrix refers to the product of a matrix and a number. The scalar is used to multiply each element in the matrix to get the final vector. In the question the scalar is k which is a constant and the matrix is A.

in the example below 2 is the scalar

2*\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]

the final matrix will be

\left[\begin{array}{ccc}2&4&6\\8&10&12\\14&16&18\end{array}\right]

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Math riddle here
kupik [55]

Answer:

15+8+6+2=31

Step-by-step explanation:

highest no. is 15

15-7=8

31-15-8=8

middle number 8

8-6=2

CHECK: 15+8+6+2=31

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4 0
2 years ago
Please help me with this.
tatyana61 [14]

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

<h3>How to evaluate a piecewise function at given values</h3>

In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:

<h3>r(- 3): </h3>

-3 ∈ (- ∞, -1]

r(- 3) = - 2 · (- 3) + 9

r (- 3) = 15

<h3>r(- 1):</h3>

-1 ∈ (- ∞, -1]

r(- 1) = - 2 · (- 1) + 9

r (- 1) = 11

<h3>r(1):</h3>

1 ∈ (-1, 5)

r(1) = 2 · 1² - 4 · 1 - 5

r (1) = - 7

<h3>r(5):</h3>

5 ∈ [5, + ∞)

r(5) = 4 · 5 - 7

r (5) = 13

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

To learn more on piecewise functions: brainly.com/question/12561612

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In this case, the function is given as f(m), which means that the input value is represented by m.


Hence, the graph is the plot of y = f(m).


The choice of the letter used for the variable is completely arbitrary and does not change either the math or the graph. It could have been said that the function is f(x) in which case the graph would be y = f(x). Nothing changes but the name that you use.

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