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Harrizon [31]
3 years ago
10

What kind of question will ask us to use this type of format to evaluate the integral instead of doing the regular integral eval

uation?

Mathematics
1 answer:
ANEK [815]3 years ago
6 0

Answer:

Great work!

Step-by-step explanation:

These kind of questions are calculated through Riemann Sum. You can evaluate any definite integral using the Riemann Sum. It should be in the following form:

f(x)dx on the interval [a, b], or

\int _a^b\:f\left(x\right)dx

Now f(x) is simply y. Therefore in this example y = x^3 - 6x. We just need the sufficient amount of data to apply the Riemann Sum, including the interval [a, b] that bounds the area, and the the number of rectangles 'n' that we need to use.

Consider an easier approach to this question: (First attachment)

Graph: (Second Attachment)

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B. Using your answer in letter a or write the equation of the line in the form Ax + By = C
Svetradugi [14.3K]

Answer:

Step-by-step explanation:

(1, 5.5) ; (2, 9)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\

         = \frac{9-5.5}{2-1}\\\\=\frac{3.5}{1}\\\\= 3.5

         = 7/2

m = 7/2 ; (2 , 9)

y - y1 =m(x -x1)

y - 9 = \frac{7}{2}(x- 2)\\\\y - 9 = \frac{7}{2}x - \frac{7}{2}*2\\\\y -9 = \frac{7}{2}x - 7\\\\y = \frac{7}{2}x - 7 + 9\\\\y = \frac{7}{2}x + 2

Multiply the equation  by 2

2y = 2*\frac{7}{2}x + 2 *2\\\\2y = 7x + 4\\\\7x - 2y = -4\\

         

4 0
2 years ago
What is the diffrence between 6 thirty-sixes and 4 thirty-sixes.?
Lilit [14]
6 thirty-sixes -4 thirty-sixes = 2 thirty-sixes
2 thirty-sixes = 2•36 = 72
6 0
3 years ago
Which equation is represented by the table? x y (x, y) 0 2 (0, 2) 1 –1 (1, –1) 2 –4 (2, –4) A. y = –2x B. y = x – 1 C. y = 2x D.
SashulF [63]
Answer:  [D]:    y  =  -3x  +  2  .
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4 0
3 years ago
PLEASE ANSWER NUMBER 17
zzz [600]
A=1 and 2
B=2 and 4
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D=1,2,4,and 8
7 0
3 years ago
What should be added to (-5 a2b - 9 ab) to get <br>a2b + 3 ab?​
Doss [256]

Based on given conditions,

a²b + 3 ab - (-5 a²b - 9 ab)

→a²b + 3 ab + 5 a²b + 9 ab

→(a²b + 5 a²b) + (3ab + 9 ab

Now collecting the coefficients and adding them,

(1 + 5)a²b + (3 + 9)ab

→6 {a}^{2}b + 12ab

Hence, the <u>6</u><u>a</u><u>²</u><u>b</u><u> </u><u>+</u><u> </u><u>1</u><u>2</u><u>a</u><u>b</u> should be added.

5 0
2 years ago
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