Find the area of a trapezoid with bases that measure 9.2 CM and 7.7 cm and height 6.8 cm

2 answers:

8 0

$\bf \textit{area of a trapezoid}\\\\
A=\cfrac{h(a+b)}{2}~~
\begin{cases}
a,b=\stackrel{bases}{parallel~sides}\\
h=height\\
---------\\
a=9.2\\
b=7.7\\
h=6.8
\end{cases}\implies A=\cfrac{6.8(9.2+7.7)}{2}$

8_murik_8 [283]3 years ago

5 0

Answer:

The area of a trapezoid is 57.46 cm².

Step-by-step explanation:

Formula

$Area\ of\ trapezoid = \frac{(a + b)}{2}\times h$

Where a, b are the two parallel bases of the trapezoid.

h is the height of the trapezoid.

As given

Trapezoid with bases that measure 9.2 cm and 7.7 cm and height 6.8 cm.

Put in the formula

$Area\ of\ trapezoid = \frac{(9.2 + 7.7)}{2}\times 6.8$

$Area\ of\ trapezoid = \frac{16.9}{2}\times 6.8$

$Area\ of\ trapezoid = 8.45\times 6.8$

Area of trapezoid = 57.46 cm²

Therefore the area of a trapezoid is 57.46 cm².

You might be interested in

For two functions, a(x) and b(x), a statement is made that a(x) = b(x) at x = 2. What is definitely true about x = 2? (2 points)

Irina-Kira [14]

The statement that is definitely true about x = 2 is Both a(x) and b(x) have the same output value at x = 2.

<h3>How to find the statement that is true about the functions a(x) = b(x) at x = 2?</h3>

If we have two functions a(x) and b(x), a statement is made that a(x) = b(x) at x = a, this implies that the values of the functions a(x) and b(x) are equal at x = a.