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2 years ago

Find the area of a trapezoid with bases that measure 9.2 CM and 7.7 cm and height 6.8 cm

2 answers:

8 0

$\bf \textit{area of a trapezoid}\\\\
A=\cfrac{h(a+b)}{2}~~
\begin{cases}
a,b=\stackrel{bases}{parallel~sides}\\
h=height\\
---------\\
a=9.2\\
b=7.7\\
h=6.8
\end{cases}\implies A=\cfrac{6.8(9.2+7.7)}{2}$

8_murik_8 [283]2 years ago

5 0

Answer:

The area of a trapezoid is 57.46 cm².

Step-by-step explanation:

Formula

$Area\ of\ trapezoid = \frac{(a + b)}{2}\times h$

Where a, b are the two parallel bases of the trapezoid.

h is the height of the trapezoid.

As given

Trapezoid with bases that measure 9.2 cm and 7.7 cm and height 6.8 cm.

Put in the formula

$Area\ of\ trapezoid = \frac{(9.2 + 7.7)}{2}\times 6.8$

$Area\ of\ trapezoid = \frac{16.9}{2}\times 6.8$

$Area\ of\ trapezoid = 8.45\times 6.8$

Area of trapezoid = 57.46 cm²

Therefore the area of a trapezoid is 57.46 cm².

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Move the decimal point in 250,000 to The left as many places as necessary to. Find a number that is greater than or equal to 1 a

kotykmax [81]

Your answer is 2.50 (And the rest of the 0s, but they aren't needed...) Since that is greater then 1, but less than 10.

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3 years ago

Read 2 more answers

Joanne has a cylindrical, above ground pool. the depth (height) of the pool is 1/2 of its radius, and the volume is 1570 cubic f

diamong [38]

Answer:

314 ft²

Step-by-step explanation:

Data provided in the question:

Depth (height) of the pool = $\frac{1}{2}$ of its radius

let the radius be 'r' ft

thus,

Depth (height) of the pool, h = $\frac{r}{2}$ ft

Volume of the pool = 1570 ft³

also,

Volume of cylinder = πr²h

thus,

1570 ft³ = πr²h

1570 ft³ = $\pi r^2(\frac{r}{2})$

3140 = 3.14 × r³ [ π = 3.14 ]

r³ = 1000 ft³

r = 10 ft

Thus,

Area of the bottom surface = πr²

= 3.14 × 10²

= 314 ft²

5 0

2 years ago

If 3 3/4 lb of candy costs 20 .25 how many would 1 lb of candy cost

Mrac [35]

solution:

$\frac{c}{w}=\frac{20.25}{\frac{3}{4}}\\\frac{c}{1}=\frac{20.25\times 4}{3}\\\frac{c}{1}=\frac{81}{3}\\c=27\\1Ib cost is \$ 27$

3 0

2 years ago

A psychologist is interested in knowing whether adults who were bullied as children differ from the general population in terms

MissTica

Answer:

$t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74$

The degrees of freedom are given by:

$df =n-1= 25-1=24$

Now we can calculate the p value with the following probability:

$p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}$

And for this case since the p value is lower compared to the significance level $\alpha=0.05$ we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

Step-by-step explanation:

For this case we have the following info given:

$\bar X = 39.5$ represent the sample mean

$s =6.6$ represent the sample deviation

$\mu = 30.6$ represent the reference value to test.

$n = 25$ represent the sample size selected

The statistic for this case is given by:

$t =\frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

And replacing we got:

$t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74$

The degrees of freedom are given by:

$df =n-1= 25-1=24$

Now we can calculate the p value with the following probability:

$p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}$

3 0

3 years ago

How many 4' x 8' sheets of plywood are required to cover a floor that is 9 m by 16 m?

Xelga [282]

Assuming no border or waste, 9m by 16 m translates to 29.52' x 52.49'.
use 32/8=4 sheets of plywood to cover the width on the 8' side.
For the length, use 52/4=13 pieces on the 4' side.
This gives a total of 4*13=52 sheets.
The extra 0.49' x 29.52 can be covered using the extra from the last four sheets for the width.

Check:
Area to be covered: 29.52*52.49=1550 sq. ft.
Area of plywood supplied = 52*4'x8'= 1664 sq. ft, > 1550 sq.ft.

8 0

2 years ago