Question

Find the area of a trapezoid with bases that measure 9.2 CM and 7.7 cm and height 6.8 cm

Answer 1

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\ ---------\\ a=9.2\\ b=7.7\\ h=6.8 \end{cases}\implies A=\cfrac{6.8(9.2+7.7)}{2}$

Answer 2

Answer:

The area of a trapezoid is 57.46 cm².

Step-by-step explanation:

Formula

$Area\ of\ trapezoid = \frac{(a + b)}{2}\times h$

Where a, b are the two parallel bases of the  trapezoid.

h is the height of the trapezoid.

As given

Trapezoid with  bases that measure 9.2 cm and 7.7 cm and height 6.8 cm.

Put in the formula

$Area\ of\ trapezoid = \frac{(9.2 + 7.7)}{2}\times 6.8$

$Area\ of\ trapezoid = \frac{16.9}{2}\times 6.8$

$Area\ of\ trapezoid = 8.45\times 6.8$

Area of trapezoid = 57.46 cm²

Therefore the area of a trapezoid is 57.46 cm².