A = lw is both a literal equation and a formula. true false

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

7 0

3 years ago

Only 4 more left........................

Luden [163]

Answer:

2x^2 - 3x - 1

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the value of x in the triangle shown below. 4 5 Choose 1 answer

nikitadnepr [17]

Answer:

x=3

Step-by-step explanation:

using the pythagorean theorem, c^2=a^2+b^2

5^2=x^2+4^2, x=3

4 0

3 years ago

If f(x)=-4x-5 and g(x)= 3-x, what is g(-4) +f(1)? A.-10 B.7 C.-9 D.-2

Kisachek [45]

Answer:

-2

Step-by-step explanation:

sustitue -4 into x for 3-x which would equal 7 because a negative times a negative equals positive. Then substitue 1 in for x in -4x-5 which would get you -9

give brainliest pls

7 0

3 years ago

Farmer Kipp sold 25 horses for a total of $7500 in January and 25 horses for a total of $10500 in February. What is the average

insens350 [35]

Answer:

So Average Price of horse is $360

Step-by-step explanation:

Given:

25 horses sold in January for $ 2500

25 horses sold in February for $10500

TO find:

Average price of horse = ?

Solution:

Average price is usually found out by adding all the values and dividing by its total no of values

Now in our case

Total Horse = 25 + 25

= 50

Total Money = $7500 + $10500

= $18000

Average Price $=\frac{total price}{total horses}$

Average Price $=\frac{18000}{50}$

=$360

So Average Price of horse is $360

3 0

3 years ago