If 5 consecutive integers is 205,
then a + b + c + d + e = 205
but also, each integer is separated by a difference of 1
⇒ a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205
⇒ 5a + 10 = 205
⇒ 5a = 195
⇒ a = 39
∴ third term = 39 + 2
= 41
Answer:
Step-by-step explanation:
Answer:
d= all the x values
r=all the y values
Step-by-step explanation:
Answer:
her language arts hw takes longer and it takes 2/9 hr longer
Step-by-step explanation:
first of all, 4/9 > 2/9
4/9-2/9=2/9