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AysviL [449]
2 years ago
14

WILL GIVE 100 POINTS AND MAYBE BRAINLIEST

Mathematics
1 answer:
Anon25 [30]2 years ago
4 0

Answer:

y=\cfrac{1}{2}\;x-4

x   |  y

10    1    = 1/2 (10) -4=5-5= 1

-2    -5  = 1/2(-2)-4=-1-4= -5

4     -2   = 1/2(4)-4=2-4= -2

-8    -8  = 1/2(-8)-4=-4-4= -8

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tekilochka [14]
The answer would be a^9 (a to the ninth power) because you would add the exponents.
5 0
3 years ago
Write an expression with five different terms that is equivalent to 8x^2 + 3x^2 + 3y
Misha Larkins [42]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

An expression having five terms which is equivalent to above term is :

  • 5x {}^{2}  + 3 {x}^{2}  + 3{x}^{2}  +4y - y

3 0
3 years ago
\int\limits^0_∞ cos{x} \, dx
JulijaS [17]

Answer:

\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty)

General Formulas and Concepts:

<u>Pre-Calculus</u>

  • Unit Circle
  • Trig Graphs

<u>Calculus</u>

  • Limits
  • Limit Rule [Variable Direct Substitution]:                                                     \displaystyle \lim_{x \to c} x = c
  • Integrals
  • Integration Rule [Fundamental Theorem of Calculus 1]:                             \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)
  • Trig Integration
  • Improper Integrals

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \int\limits^0_\infty {cos(x)} \, dx

<u>Step 2: Integrate</u>

  1. [Improper Integral] Rewrite:                                                                         \displaystyle  \lim_{a \to \infty} \int\limits^0_a {cos(x)} \, dx
  2. [Integral] Trig Integration:                                                                             \displaystyle  \lim_{a \to \infty} sin(x) \bigg| \limits^0_a
  3. [Integral] Evaluate [Integration Rule - FTC 1]:                                               \displaystyle  \lim_{a \to \infty} sin(0) - sin(a)
  4. Evaluate trig:                                                                                                 \displaystyle  \lim_{a \to \infty} -sin(a)
  5. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  -sin(\infty)

Since we are dealing with infinity of functions, we can do a numerous amount of things:

  • Since -sin(x) is a shift from the parent graph sin(x), we can say that -sin(∞) = sin(∞) since sin(x) is an oscillating graph. The values of -sin(x) already have values in sin(x).
  • Since sin(x) is an oscillating graph, we can also say that the integral actually equates to undefined, since it will never reach 1 certain value.

∴  \displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty) \ or \ \text{unde}\text{fined}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Improper Integrals

Book: College Calculus 10e

7 0
3 years ago
What is the slope of the line through the points (-2, -1) and (4, 3)? ​
Natalka [10]

Answer:

#2 option: \frac{2}{3}

Step-by-step explanation:

slope=\frac{rise}{run} =\frac{y^2-y^1}{x^2-x^1}

\frac{3-(-1)}{4-(-2)}=\frac{-4}{-6} =\frac{-2}{-3} =\frac{2}{3}

=  \frac{2}{3}

8 0
2 years ago
Sarah Jane, the crew artist, has a fancy 360- degree camera. She can walk at a rate of 2 miles per hour when carrying it. How lo
Mrrafil [7]

Answer:

1 hour and 30 minutes.

Step-by-step explanation:

While carrying her fancy 360-degree camera, a crew artist Sarah Jane can walk at a rate of 2 miles per hour.

We are asked to determine the time required by Sarah to walk to a place that is 3 miles away from her.

Since Sarah can walk at a rate of 2 miles per hour.

Hence, she walks 3 miles in \frac{3}{2} hours i.e. 1 hour and 30 minutes.  (Answer)

{Here we have used the unitary method assuming that Sarah walks at a constant rate}

5 0
3 years ago
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