Identify the stimuli.

Select the correct location on the image. Keiko’s teacher was discussing the theory of endosymbiosis. She asked Keiko to mark th

const2013 [10]

Mitochondria in animal cells, while mitochondria and chloroplast in plant cells most closely resembled prokaryotes.

<h3>What do you mean by endosymbiotic theory?</h3>

This theory states that organelles such as mitochondria and chloroplast in eukaryotic cells were once prokaryotic microbes.

These organelles when occupied in prokaryotes divide by binary fission. But they become a part of the eukaryotic cell now and result in a symbiosis relationship between each other.

Therefore, Mitochondria in animal cells, while mitochondria and chloroplast in plant cells most closely resembled prokaryotes.

To learn more about Endosymbiotic theory, refer to the link:

brainly.com/question/1698852

6 0

3 years ago

What will happen if bone marrow gets destroyed ?

Rus_ich [418]

Bone marrow contains stem cells. stem cells can develop into red blood cells (carry oxygen), white blood cells (provide immunity), and platelets (aid in clotting)

if the bone marrow is destroyed or does not function properly leukemia (cancer causing abnormal white blood cells) or aplastic anemia (bone marrow doesnt make red blood cells) could develop.

6 0

4 years ago

____________ is the state of maintaining a stable internal environment despite changing external conditions.

natka813 [3]

Your fill in the blank answer is: Homeostasis

4 0

3 years ago

Read 2 more answers

Look at this picture of a whale shark. Which question about whale sharks is nonscientific?

almond37 [142]

You need to attach a picture

6 0

4 years ago

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny pl

nalin [4]

Here is the complete question

The seeds in bush bean pods are each the product of an independent fertilization event. Green seed color is dominant to white seed color in bush beans.

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny plant will consist of:

A) 4 green and 2 white seeds?

B) all white seeds?

C) at least 5 white seeds?

Answer:

A) 0.3

B) 0.0002

C) 0.001

Explanation:

Let the allele for Green plant be = P

Let the allele for white plant be = p

Let the heterozygous plant be Pp, if self fertilization occurs we have:

P p

P PP Pp

p Pp pp

From the punnet square above, we have the following cross;

PP, Pp, Pp, pp

Since P is dominant to p; we have a phenotypic ratio of 3:1 between the dominant phenotype ( PP, Pp, Pp ) and recessive phenotype ( pp )

NOW, the probability for the green plant(i.e PP or Pp) will be: $Pr(G)=\frac{3}{4}$

the probability for the white plant (pp) will be: $Pr (W)= \frac{1}{4}$

A)

what is the probability that 6 seeds in a single pod of the progeny plant will consist of 4 green and 2 white seeds?

$Pr(4G2W)$ = $(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

The probability includes the use of permutation:

$Permutation(P)=\frac{6!}{(4!*2!)} * (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

= $15*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

= 0.2966

≅ 0.3

B)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of all white seeds?

Since probability for white seed = $\frac{1}{4}$

The probability that 6 seeds will consist of all white seeds will be = $(\frac{1}{4})^6$

= 2.44 × 10⁻⁴

= 0.000244

≅ 0.0002

C)

What is the probability that 6 seeds in a single pod of the progeny plant will consist of at least 5 white seeds?

For at least 5 white seeds, the probability will consist of 5 white seeds and 6 white seeds.

For 5 white seeds; we have:

5 White and 1 Green Since there are 6 permutations.

The probability For 5 white seeds will therefore be :

$Pr(5 seeds)=(\frac{1}{4})^5*(\frac{3}{4})^1 *6$

= 7.32 × 10⁻⁴

= 0.000732

For 6 white seeds; we have:

Only one permutation for 6 whites since there will no be any presence of any green seed.

$Pr(6seeds)=(\frac{1}{4})^6$

= 2.44 × 10⁻⁴

= 0.000244

∴

The total probability for at least 5 white seeds = 0.000732 + 0.000244

= 9.76 × 10⁻⁴

= 0.000976

≅ 0.001

3 0

4 years ago