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DanielleElmas [232]
3 years ago
13

Write an inequality for the situation. all real numbers at most –9.5 or at least 5.5

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0
Hello,

If b represents any real number,

b<=-9.5
or
5.5<=b


Answer  C

dexar [7]3 years ago
3 0

Answer:

option (c) is correct.

The given expression all real numbers at most –9.5 or at least 5.5 is written as   b ≤ –9.5  or  b ≥ 5.5

Step-by-step explanation:

Given  expression all real numbers at most –9.5 or at least 5.5

We have to represent the given expression mathematically and choose the correct from given options.

Consider the given expression  all real numbers at most –9.5 or at least 5.5

Let the real number be represented by b

then the given expression contain two terms

1)  all real numbers at most –9.5  

Mathematically written as  b ≤ –9.5    .....(1)

2) all real numbers at least 5.5

Mathematically written as  b ≥ 5.5       ....(2)

Thus, the given expression   all real numbers at most –9.5 or at least 5.5 is written as   b ≤ –9.5  or  b ≥ 5.5

Thus, option (c) is correct.

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Step-by-step explanation:

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Tammy received a $70 gift card for a coffee store. She used it in buying some coffee that cost $8.41 per pound. After buying the
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Money she is left with now = $19.54

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2 years ago
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
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