Solve the system by elimination:
-2x + 2y + 3z = 0
-2x - y + z = -3
2x+ 3y + 3z = 5
1 answer:
First= -2x+2y+3z=0
= -2x+2y+3z +-2y=0+(-2y)
-2x+3z=-2y
-2x+3z=-2y+-3z
-2x=-2y-3z
Divide both by negative two
-2x/-2=-2y-3z/-2
x=y+3/2z that’s the answer.
Use this to help you with other equations
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