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natali 33 [55]
3 years ago
6

The length of a rectangle is (x plus 3) inches long, and the width is 3 2/5 inches. If the area is 15 3/10 square inches, write

and solve an equation to find the length of the rectangle??? Plz I will give you 100 points
Mathematics
1 answer:
IgorC [24]3 years ago
6 0

Answer: Explained in the step-by-step


Step-by-step explanation:

We want to isolate x, and remember, what we do to one side we do to the other:

(x+3) * 3  2/5 = 15  3/10

(x+3) * 3  2/5 divided by 3  2/5 = 15  3/10  divided by 3  2/5

x + 3 = 153/10 * 5/17

x + 3 = 765/170

x + 3 = 153/34

x + 3 = 4.5

x + 3 - 3 = 4.5 - 3

x = 1.5

Check:

(1.5+3) * 3  2/5 = 15  3/10

4.5 * 3  2/5 = 15  3/10

(3  2/5 = 3.4 and 15  3/10 = 15.3)

4.5 * 3.4 = 15.3

15.3 = 15.3

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The solution of two linear equations is (-2,2). One equations has a slope of 3. The slope of the other equation is the negative
sineoko [7]

Answer:

Its true ⇒ answer (a)

Step-by-step explanation:

* The solution of two linear equation means that this solution

  is a solution for each equation

* To check if the point is a solution of an equation

- Substitute its coordinates in the equation, if the left hand side

 is equal the right hand side, then the point is a solution

 of this equation

* Lets study our problem

- (-2 2) is the solution of two linear equations

- The slope of one equation is 3

- The slope of the second equation is the negative reciprocal

 of the slope of the first, means = -1/3

* Check the this conditions in the given equations

- In the equation y = 3x + 8 ⇒ the slope = 3

- In the equation y = -1/3 x + 4/3 ⇒ the slope = -1/3

* Now lets substitute the solution (-2 , 2) in the both equations

- First equation

∵ y = 2 ⇒ L.H.S

∵ 3(-2) + 8 = 2 ⇒ R.H.S

∵ L.H.S = R.H.S

∴ (-2 , 2) is a solution of the equation y = 3x + 8

- Second equation

∵ y = 2 ⇒ L.H.S

∵ (-1/3)(-2) + 4/3 = 2/3 + 4/3 = 6/3 = 2 ⇒ R.H.S

∵ L.H.S = R.H.S

∴ (-2 , 2) is a solution of the equation y = -1/3 x + 4/3

∴ (-2 , 2) is the solution of the two equations

* Its true

5 0
3 years ago
Read 2 more answers
What is the approximate volume of the cone? Use 3.14 for π.
telo118 [61]

Answer:

About 131.95 (you may have to round up)

Step-by-step explanation:

Volume of a cone = pi(r^2)(h/3)

= pi(3^2)(14/3)

= pi(9)(4 & 4/5)

= pi(43.2)

If your teacher wants an exact number, you have to multiply 43.2 y whatever your teacher says to shorten pi to, usually 3.14. The about 131.95 is from 43.2*3.14 I think.

8 0
2 years ago
Simplify ¾(8w+28)-10+w please :)
Zigmanuir [339]

Answer:

7w+11

Step-by-step explanation:

GEMDAS

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3 years ago
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
The first 2 terms of an ap is -2 and 3 how many terms are needed for the sum to be equal to 306 ​
Zepler [3.9K]

Answer:

306

Step-by-step explanation:

-2 + 3 = 1

so really it would take 306 times to get to this

6 0
3 years ago
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