Ask question

Ask question

All categories

3 years ago

6

The length of a rectangle is (x plus 3) inches long, and the width is 3 2/5 inches. If the area is 15 3/10 square inches, write

and solve an equation to find the length of the rectangle??? Plz I will give you 100 points

1 answer:

IgorC [24]3 years ago

6 0

Answer: Explained in the step-by-step

Step-by-step explanation:

We want to isolate x, and remember, what we do to one side we do to the other:

(x+3) * 3 2/5 = 15 3/10

(x+3) * 3 2/5 divided by 3 2/5 = 15 3/10 divided by 3 2/5

x + 3 = 153/10 * 5/17

x + 3 = 765/170

x + 3 = 153/34

x + 3 = 4.5

x + 3 - 3 = 4.5 - 3

x = 1.5

Check:

(1.5+3) * 3 2/5 = 15 3/10

4.5 * 3 2/5 = 15 3/10

(3 2/5 = 3.4 and 15 3/10 = 15.3)

4.5 * 3.4 = 15.3

15.3 = 15.3

You might be interested in

If a cold object is in contact with a warm object,in which direction is heat transferred

forsale [732]

Answer:towards the cold object

Step-by-step explanation:

because heat goes from warmer places to cooler places.

8 0

3 years ago

Solve for x.<br> y = (5+x}m<br> Answer?

Tanzania [10]

Answer:

x=ym−4

Step-by-step explanation:

y=(4+x)m

Here we have one equation with three unknowns. This cannot be "solved". We can only express one variable in terms of the other two.

Let's isolate x.

Divide through by m

ym=4+x

x=ym−4

(I really hope this helps)

4 0

3 years ago

A test score in the 97th percentile would be considered:

seropon [69]

<span>THE ANSWERS IS VERY HIGH..................A test score in the 97th percentile would be considered very high</span>

8 0

3 years ago

Read 2 more answers

Consider the diagram below. which of the following represents the values x,y and z?

Gemiola [76]

Answer:

$x=4\sqrt{6}\ units$

$y=4\sqrt{2}\ units$

$z=4\sqrt{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

In the right triangle ABD

Applying the Pythagorean Theorem

$x^2=y^2+(12-4)^2$

$x^2=y^2+64$

$y^2=x^2-64$ ----> equation A

step 2

In the right triangle BDC

Applying the Pythagorean Theorem

$z^2=y^2+4^2$

$z^2=y^2+16$

$y^2=z^2-16$ ----> equation B

step 3

In the right triangle ABC

Applying the Pythagorean Theorem

$12^2=x^2+z^2$

$144=x^2+z^2$ ----> equation C

step 4

Equate equation A and equation B

$x^2-64=z^2-16$

$x^2=z^2+48$ -----> equation D

step 5

substitute equation D in equation C

$144=z^2+48+z^2$

solve for z

$2z^2=144-48$

$2z^2=96$

$z^2=48$

$z=\sqrt{48}\ units$

simplify

$z=4\sqrt{3}\ units$

Find the value of x

$x^2=z^2+48$

$x^2=48+48=96$

$x=\sqrt{96}\ units$

$x=4\sqrt{6}\ units$

Find the value of y

$y^2=z^2-16$

$y^2=48-16$

$y^2=32$

$y=\sqrt{32}\ units$

$y=4\sqrt{2}\ units$

3 0

3 years ago

Art [367]

Answer:

.

<_>

.

()_()

.

Step-by-step explanation:

5 0

3 years ago