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2 years ago

What will make the equation true 4x + 3 = 11

Mathematics

2 answers:

Inga [223]2 years ago

7 0

2. the answer is 2 because 4(2) = 8 and 8+3=11

ValentinkaMS [17]2 years ago

5 0

Answer: 2

Step-by-step explanation:

4x+3=11

-3 -3

4x=8

\4 \4

X=2

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12x-13x write an equivalent expression.

harina [27]

Answer:

-x

Step-by-step explanation:

12x-13x is -1x which can also be written as -x

5 0

2 years ago

A farmer wants to fence in a rectangular field that encloses 3600 square feet. One side of the field is along a river and does n

andriy [413]

Answer:

C(x) = $\$3.50(\frac{x^2+7200}{x})$

Step-by-step explanation:

Data provided in the question:

Area of the field = 3600 square feet

Fencing charges = $3.50 per foot

Let the side along the river be 'x' feet and the other side of the 'B'

now,

Area of rectangle = Bx = 3600 square feet

B = $\frac{3600}{x}$ feet

and total length to be fenced = x + 2B

therefore,

Total cost of fencing = Fencing charges × total length to be fenced

Total cost of fencing = $3.50 × ( x + 2B )

substituting the value of B from (1)

Total cost of fencing, C(x) = $\$3.50(x+2\times\frac{3600}{x})$

C(x) = $\$3.50(\frac{x^2+7200}{x})$

4 0

3 years ago

If angle∠ A and angle∠ B are supplementary angles and angle∠ A is eighteight times as large as angle∠ B, find the measures of a

Shalnov [3]

A = 8B
A + B = 180
8B + B = 180
9B = 180
B = 20
A = 8 * 20 = 160

4 0

2 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

2 years ago

What happens to an image when it is enlarged using scale factor between -1and1

adell [148]

I have done this question before but i can’t remember

6 0

3 years ago