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ioda
3 years ago
10

Let f(x)=2x^2−8 .

Mathematics
1 answer:
madam [21]3 years ago
5 0
To translate a function up or down you add a constant to the function...2 units downward means you must subtract 2 from the original equation...

g(x)=f(x)-2

g(x)=2x^2-8-2

g(x)=2x^2-10
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Describe in words where cube root of 35 would be plotted on a number line. between 3 and 4, but closer to 3 between 3 and 4, but
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The ∛35 will be plotted between 3 and 4, but closer to 3 on the number line.

In basic mathematics, real numbers are shown as a fine graphic of a graduated straight line which is called a number line.

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3 0
1 year ago
2. Your friend wants to write the equation of a quadratic function 1 5. 3.r = 1) that has zeros at 3 and 3. They want to use the
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Let's expand both options, your friend's and yours, as shown below

\begin{gathered} y=(3x+1)(3x-5)=9x^2-12x-5=9(x^2-\frac{4}{3}x-\frac{5}{9}) \\ \text{and} \\ y=(x+\frac{1}{3})(x-\frac{5}{3})=x^2-\frac{4}{3}-\frac{5}{9} \end{gathered}

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\begin{gathered} y=(3x+1)(3x-5) \\ x=-\frac{1}{3} \\ \Rightarrow y=(-1+1)(-1-5)=0 \\ \text{and} \\ x=\frac{5}{3} \\ \Rightarrow y=(5+1)(5-5)=0 \\  \end{gathered}

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\begin{gathered} y=(x-\frac{5}{3})(x+\frac{1}{3}) \\ x=-\frac{1}{3} \\ \Rightarrow y=(-\frac{1}{3}-\frac{5}{3})\cdot0=0 \\ x=\frac{5}{3} \\ \Rightarrow y=0\cdot(\frac{6}{3})=0 \end{gathered}

Both your friend and you are correct. The functions are the same with exception of a constant that multiplies the whole function (a scale factor); despite that, the zeros are the same for both functions

(3x-5)(3x+1)=9(x+\frac{1}{3})(x-\frac{5}{3})

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