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enot [183]
1 year ago
14

Describe in words where cube root of 35 would be plotted on a number line. between 3 and 4, but closer to 3 between 3 and 4, but

closer to 4 between 2 and 3, but closer to 2 between 2 and 3, but closer to 3
Mathematics
1 answer:
Pani-rosa [81]1 year ago
3 0

The ∛35 will be plotted between 3 and 4, but closer to 3 on the number line.

In basic mathematics, real numbers are shown as a fine graphic of a graduated straight line which is called a number line.

  • Every point on a number line is considered to correspond to a real number, and every real number is assumed to correspond to a point.
  • The integers are typically shown as lines of specially chosen, evenly spaced dots.
  • Even though the image only shows the integers from -3 to 3, as well as values that are in between the integers, the product contains all real numbers, going forever in both directions.
  • When teaching the very foundations , addition and subtraction with negative numbers, it is widely used as a teaching technique.

We know that 35 lies between 27 and 64 , and 27 = 3³ and 64 = 4³.

Hence the ∛35 will be plotted between 3 and 4 and since 35 is closer to 27 than 64 , therefore it will be closer to 3.

To learn more about the number-line visit:

brainly.com/question/13425491

#SPJ4

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e-lub [12.9K]

Answer:

a_0 = -8

a_1=-6

x^2 +y^2 -8x - 6y = 0

Step-by-step explanation:

The equation of the circle has the following form

x^2 + y^2 + a_0x + a_1y=0

The equation of the circle has the following form

We know that the circle goes through the following points

(1, 7)

(8, 6)

(7, -1).

Then we substitute the values of x and y in the equation

<u>For (1, 7)</u>

(1)^2 + (7)^2 + a_0(1) + a_1(7)=0

1 + 49 + a_0 + 7a_1=0

a_0 + 7a_1=-50    (1)

<u>For  (8, 6)</u>

(8)^2 + (6)^2 + a_0(8) + a_1(6)=0

64 + 36 + 8a_0 + 6a_1=0

8a_0 + 6a_1= -100    (2)

With these equations is enough to solve the system

a_0 + 7a_1=-50    (1)

8a_0 + 6a_1= -100    (2)

Multiply the equation (1) by -8 and add it to the equation (2)

-8a_0 - 56a_1=400    (1)

8a_0 + 6a_1= -100    (2)

-----------------------------------------------------

-50a_1 = 300\\\\a_1 = -6

Then

a_0 + 7(-6) = -50\\\\a_0 = -50+42\\\\a_0=-8

Finally the equation is:

x^2 +y^2 -8x - 6y = 0

7 0
3 years ago
) Naomi's graduation picnic costs $7 for every attendee. At most how many attendees
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ANSWER:
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6 0
3 years ago
A study is performed in a large southern town to determine whether the average amount spent on food per four-person family in th
hoa [83]

Step-by-step explanation:

H0: u = 150

H1: u ≠ 150

Total sum = 15933.24

N = 100

Mean = 15933.24/100

= 159.3324

σ² = 25954.03 - (159.3324)²/100

σ² = 556.213

σ = √556.213

σ = 23.8162

Testing hypothesis

t = (bar x - u)/ σ/√n

= 159.3324-150/23.8162/√100

= 3.91

We will have a p value of 0.02

0.0002 < 0.01

We reject null hypothesis at 1% level of significance

C. Mean = 159.3324

Se= 2.3936

Df = 100-1 = 99

Critical value at 0.01 = +-2.626

T = x-u/s.e

= -2.626 =( x -150)/2.3936

When we cross multiply and solve this

X = 143.714 for the lower tail

2.626 = (x-159)/2.3936

= 156.286 for upper tail.

We therefore reject H0 at

Bar X <= 143.71

Bar X >= 156.286

At 10%

Critical t = 1.660

-1.660 = (x - 150)/2.3936

Solving this ,

X =146.02 at the lower tail

1.660 = (x-150)/2.3936

X = 153.97

We reject H0 at

X<= 146.03

X>=153.97

4 0
3 years ago
(geometry) please look at attached image and help me with this question!
julsineya [31]

Answer:

  m∠AEC = 139°

Step-by-step explanation:

To make the equations easier to write, let's say all measures are in degrees, and define ...

  p = m∠AEB = 11x -12

  q = m∠CED = m∠CEB = 4x +1

Then ...

  p + 2q = 180

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  19x -10 = 180 . . . . . . . . . . . . collect terms

  19x = 190 . . . . . . . . add 10

  x = 10 . . . . . . . . . . . divide by 19

  p = 11x -12 = 110 -12 = 98

  q = 40 +1 = 41

The angle of interest is ...

  m∠AEC = p +q = 98 +41

  m∠AEC = 139 . . . . degrees

8 0
3 years ago
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