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Kryger [21]
3 years ago
12

Find the surface area of the ball shown. Use 3.14 for pie.

Mathematics
1 answer:
miskamm [114]3 years ago
7 0

Answer:

\displaystyle S _{ \text{sphere}} =3629.84 {cm}^{2}

Step-by-step explanation:

we are given a ball

remember that,a ball is a Sphere

thus,

\displaystyle S _{ \text{sphere}} = 4\pi {r}^{2}

given that, redious is 17 cm

substitute:

\displaystyle S _{ \text{sphere}} = 4 \times \pi  \times {17}^{2}

simplify square:

\displaystyle S _{ \text{sphere}} = 4 \times \pi  \times 289

substitute the approximate value of π:

\displaystyle S _{ \text{sphere}} = 4 \times 3.14  \times 289

simplify multiplication:

\displaystyle S _{ \text{sphere}} =3629.84

hence, the surface area of the sphere is <u>3</u><u>6</u><u>2</u><u>9</u><u>.</u><u>8</u><u>4</u><u> </u><u>cm²</u>

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A. Quadratic trinomial

Step-by-step explanation:

You can easily eliminate B and C because trinomial means there are three terms. B has monomial (one term) and C has binomial (two terms).

Now you have A and D. D is cubic which means the first term (4x²) would have to be cubed (4x³). Quadratic means it is squared.

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At a quiz competition for every question team A answered correctly team B answered 2 questions correctly. The ratio of the numbe
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3 years ago
Find S12 for geometric series: (-7.5) + 15 + (-30) + ...
kolezko [41]

Answer:

S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5

Step-by-step explanation:

Given the sequence to find the sum up-to 12 terms

(-7.5) + 15 + (-30) + ...

As we know that

A geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

\frac{15}{\left(-7.5\right)}=-2,\:\quad \frac{\left(-30\right)}{15}=-2

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=-2

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=\left(-7.5\right)

a_n=a_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=\left(-7.5\right)\left(-2\right)^{n-1}

a_n=-\left(-2\right)^{n-1}\cdot \:7.5

\mathrm{Geometric\:sequence\:sum\:formula:}

a_1\frac{1-r^n}{1-r}

\mathrm{Plug\:in\:the\:values:}

n=12,\:\spacea_1=\left(-7.5\right),\:\spacer=-2

  =\left(-7.5\right)\frac{1-\left(-2\right)^{12}}{1-\left(-2\right)}

  =-7.5\cdot \frac{1-\left(-2\right)^{12}}{1+2}

\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

  =-\frac{-30712.5}{1+2}          ∵  \left(1-\left(-2\right)^{12}\right)\cdot \:7.5=-30712.5

 =-\frac{-30712.5}{3}

 =\frac{30712.5}{3}

 =10237.5

Thus, S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5        

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Answer:

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First of 25,000 miles =8,000 dollars to the cars worth so the maxium account you can add to the mileage is 10,000 in order to keep the regulations and guidelines of car companies.

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