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sergejj [24]
3 years ago
7

What is the answer to 6x^3+2x-18=0

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

around 1.3

Step-by-step explanation:

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Make a table of values for the equation.<br> y = 3x + 2
Rzqust [24]
Tables are easy to make when u have the equation. Just simply sub any number in for x and solve for y

y = 3x + 2...lets let x = 0
y = 3(0) + 2
y = 2.....so when x = 0, y = 2....(0,2)

y = 3x + 2....lets let x = 1
y = 3(1) + 2
y = 3 + 2
y = 5....so when x = 1, y = 5....(1,5)

y = 3x + 2.....let x = 2
y = 3(2) + 2
y = 6 + 2
y = 8....so when x = 2, y = 8...(2,8)

u can find more point if u need to...

now make a table..

         x            y
        0             2
        1             5
        2             8
and like I said, if u need more numbers for ur table, just do like I did above :)
7 0
3 years ago
Read 2 more answers
Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7
Dima020 [189]

Answer:

The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

\dfrac{\textrm factor of P}{\textrm factor Q} ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial ,  P = -7 , Q = 4

Now , \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}

I.e  \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q} = \frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }

Or, The rational zero are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1

Hence The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  Answer

7 0
3 years ago
Each pack of batteries cost $21. How many i can buy if i have $63?
Rashid [163]

Each pack of batteries cost $21 each.
And then you have $63.

The operation to be used: Division.

63 ÷ 21 ==

Answer: 3


= You can buy 3 packs of batteries with your $63.

6 0
3 years ago
Read 2 more answers
Solve for x in x²+8x+15=0 in factorisation method ​
Genrish500 [490]

Answer: x=-5, -3

Step-by-step explanation:

x^2 +8x+15=0\\\\(x+5)(x+3)=0\\\\x=-5, -3

7 0
1 year ago
The graph of the function f(x) = (x − 3)(x + 1) is shown.
AVprozaik [17]

The expression that describes all of the values for which the graph is positive and decreasing is all real values of x where x < -1

<h3>Which describes all of the values for which the graph is positive and decreasing?</h3>

The equation of the function is given as:

f(x) = (x - 3)(x + 1)

When the value of the graph is positive, we have:

f(x) > 0

So, the function becomes

(x - 3)(x + 1) > 0

Split the above inequality

x - 3 > 0 and x + 1 > 0

Solve for x in the inequalities

x > 3 and x > -1

Hence, the expression that describes all of the values for which the graph is positive and decreasing is all real values of x where x < -1

Read more about intervals at:

brainly.com/question/1503051

#SPJ1

3 0
1 year ago
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