Answer:100
Step-by-step explanation:
There are ten total people:
10C3
10!/(7!×3!) = 120
Note: but that includes all the cases where there are no senior partners
So firstly let figure out the number of cases where there are no senior partners
because there are 6 junior partners
6C3
= 6!/(3!×3!) = 20
120 - 20 = 100 or the number of possible groups where there is at least 1 senior partner.
Answer:
you have to add
Step-by-step explanation:
Answer:
40
Step-by-step explanation:
Let Ted be x.
Ed is 7 years older = x + 7
Ed = (3/4)Ted
(x + 7) = (3/4)x
x + 7 = 3x/4
x - 3x/4 = -7
x/4 = -7
x = -28, Ted = -28 years.
(x + 7) = -28 + 7 = -21, Ed = -21 years
Goodness. We had negative numbers for the ages, well does that make sense? No it doesn't.
Our answer is correct. But the sense in the question is lacking. The question has been wrongly set.
<span>We might assume negative ages to mean before they came into the world, before birth! </span>
Hello from MrBillDoesMath!
Answer:
8
Discussion:
Let the number be "n". Then the question states that
3n - 15 = (n/2) + 5 => multiply both sides by 2
6n - 30 = n + 10 => subtract n from both sides
5n - 30 = 10 => add 30 to both sides
5n = 30 + 10 = 40 => divide both sides by 5
n = 40/5 = 8
Thank you,
MrB
