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marta [7]
3 years ago
14

your local radio station is having their yearly MP3 player and concert giveaway. For one minute every 5th caller will win an MP3

player and every 7th caller. will win concert tickets. You were just the first caller to win both an MP3 player and concert tickets! What number were you?
Mathematics
2 answers:
V125BC [204]3 years ago
8 0
You are the 35th caller 
7x5=35, with that being 35 you cannot be the 6th because you are still going to be 1 short and 1 more. So multiply then to get your answer 35

Ivahew [28]3 years ago
3 0
You were the 35th caller, 5 and 7 have a product of 35
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If a figure is translated 5 units down and 3 units right, how do you represent it algebraically
qwelly [4]

Answer

(x+3) -5

Step-by-step explanation:

plug the values into the parent transformation equation to its rightful places

6 0
3 years ago
Please please help me with this thank you
Alecsey [184]
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3 0
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How to solve 2m - 3 = 13
Virty [35]

Answer:

m=8

Step-by-step explanation:

8 0
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Read 2 more answers
Find 2 numbers who product is 15 and sum is 16.​
Marizza181 [45]

Answer:

15 and 1

Step-by-step explanation:

x and y are two numbers.

Two equations:

x · y = 15

x + y = 16

Rearrange one of the equations (I'll rearrange the sum equation):

x + y = 16

x = 16 - y

Substitute that to the other equation and solve for y:

x · y = 15

(16 - y) · y = 15

16 - y · y = 15

16 - y² = 15

-y² = 15 - 16

-y² = -1

y² = 1

y = √1

y = 1

Now substitute that to any of the equation and solve for x (in here, I'll choose the multiplication one):

x · y = 15

x · 1 = 15

x = 15

Now verify:

15 · 1 = 15

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This is correct

6 0
3 years ago
PLEASE help with these questions??<br> there are 7 of them!<br> Thank you!!
svetlana [45]
We know in these kind of triangles that have a 90 degrees angle, we can do:

{a}^{2} + {b}^{2} = {c}^{2}

so the first question:

\sqrt{ {99}^{2} + {20}^{2} } = 101

and then:

b = \sqrt{ {17}^{2} - {15}^{2} } = 8

so , when you want to rationalize , usually you must multiply the irrational factor as 1:

\frac{ \sqrt{15} }{ \sqrt{15} } = 1

so , now multiply:

\frac{3}{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{3 \sqrt{15} }{15} = \frac{ \sqrt{15} }{5}

in the next question,we know negative numbers in radical don't have any solution so 2 is correct,

4 0
3 years ago
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