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2 years ago

Round 3.047 to the nearest 100th

2 answers:

8 0

Round 3.047 to the nearest 100th To visually illustrate the rounding off of the values as said to the nearest hundredths. We can first disband the digit to simpler values using the expanded form:
1. 3 = ones 
2. 0. 04 = hundredths 
3. 0. 007 = thousandths
Since we have located the hundredths in 0.04 we can next round off it according to its nearest value which is 0.007. The number becomes 3.05.

Delicious77 [7]2 years ago

7 0

The next larger hundredth is 3.05 .
The next smaller hundredth is 3.04 .

3.047 is closer to 3.05 than it is to 3.04,
so the nearest hundredth is 3.05 .

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What is the slope of the line passing through the points (1,57) and (2,27)?

alex41 [277]

Answer:

m = -30

m = slope

Step-by-step explanation:

(1,57) and (2,27)

(x1,y1) and (x2,y2)

y2 - y1. 27 - 57

---------- =. ---------- =. -30/1 = -30

x2-x1. 2 - 1

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3 years ago

Read 2 more answers

A bakery used 25% more butter this month that last month. If the bakery used 240 kilograms of butter last month, how much did it

SCORPION-xisa [38]

Answer:

300kg

Step-by-step explanation:

240(25/100)

240(.25) = 60

25% of 240 = 60, so add that 60 to get an extra 25% for this month

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3 years ago

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Un escalador sube 225m de altura. El asenso lo hizo en 3 etapas. En la primera subio un quinto en la, en la tercera un cuarto. ¿

kiruha [24]

Answer:

Segunda etapa= 123.75 metros

Step-by-step explanation:

Altura total= 225 metros

En la primera estapa subió el 20% (un quinto):

Primera etapa= 225*0.2= 45 metros

En la tercera etapa subió 25% (un cuarto):

Tercera etapa= 225*0.250 56.25 metros

Ahora debemos determinar cuánto subió en la segunda etapa:

Segunda etapa= altura total - total subido

Segunda etapa= 225 - (45 + 56.25)

Segunda etapa= 123.75 metros

6 0

2 years ago

The measure of angle A is 15°, and the length of side

dangina [55]

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$

8 0

3 years ago

Need Help with 44.. picture above

Daniel [21]

Answer:

Ok:

Step-by-step explanation:

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3 years ago