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shusha [124]
3 years ago
10

I need help with number 12 and 13 please

Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

D, 1200

Step-by-step explanation:

V of Cylinder= (pi)r^2h

r=radius h=height

we know the area of a circle which is (pi)r^2. So we can just multiply that by the height to get the answer.

100x12=1200

there

also for 12 its D

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Well twenty hundreds is equal to 2000 and eight tens is equal to 80. So, 2000x80=160000
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Given the system of equations One-third x minus two-thirds y = 7 and two-thirds x + 3 y = 11, which numbers can be multiplied by
asambeis [7]

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A  B & E

Step-by-step explanation:

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Find the AREA and PERIMETER of the triangle
iVinArrow [24]

Answer:

Area=99

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Write the square of the binomial as a polynomial: (-1 1/3p + 6q)^2
Thepotemich [5.8K]

Answer:

\frac{16}{9}p² -16pq + 36q²

Step-by-step explanation:

Given

(- \frac{4}{3}p + 6q)²

= (- \frac{4}{3}p + 6q)(- \frac{4}{3}p + 6q)

Each term in the second factor is multiplied by each term in the first factor, that is

- \frac{4}{3}p(- \frac{4}{3}p + 6q) + 6q(- \frac{4}{3}p + 6q)

= \frac{16}{9}p² - 8pq - 8pq + 36q² ← collect like terms

= \frac{16}{9}p² - 16pq + 36q²

5 0
3 years ago
Which point lies on a circle with a radius of 5 units and center at P(6,1)?
ryzh [129]

Answer:

Option B. R(2,4)

Step-by-step explanation:

we know that

If a ordered pair lie on the circle. then the ordered pair must satisfy the equation of the circle

step 1

Find the equation of the circle

we know that

The equation of the circle in center radius form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

r is the radius of the circle

(h,k) is the center of the circle

substitute the values

(x-6)^{2}+(y-1)^{2}=5^{2}

(x-6)^{2}+(y-1)^{2}=25

step 2

Verify each case

case A) Q(1, 11)

substitute the value of x=1, y=11 in the equation of the circle and then compare the results

(1-6)^{2}+(11-1)^{2}=25

25+100=25 ------> is not true

therefore

the ordered pair Q not lie on the circle

case B) R(2,4)

substitute the value of x=2, y=4 in the equation of the circle and then compare the results

(2-6)^{2}+(4-1)^{2}=25

16+9=25 ------> is true

therefore

the ordered pair R lie on the circle

case C) S(4,-4)

substitute the value of x=4, y=-4 in the equation of the circle and then compare the results

(4-6)^{2}+(-4-1)^{2}=25

4+25=25 ------> is not true

therefore

the ordered pair S not lie on the circle

case D) T(9,-2)

substitute the value of x=4, y=-4 in the equation of the circle and then compare the results

(9-6)^{2}+(-2-1)^{2}=25

9+9=25 ------> is not true

therefore

the ordered pair T not lie on the circle

7 0
3 years ago
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