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seraphim [82]
2 years ago
10

How to solve the equation

Mathematics
1 answer:
tatiyna2 years ago
8 0

Answer:

ha

Step-by-step explanation:

hahaha thanks for the points ha

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Triangle ABC has translated 2 units left and 1 unit up. What is the new location of point C?
KonstantinChe [14]

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What are the coordinates for point C?

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3 years ago
Question down below about linear equations and grapghing.
Alik [6]

The system of equations is -x + y = 4 and -2x + y = 0

<h3>How to create the system of linear equations?</h3>

To do this, we make use of the following ordered pairs

(4, 8)

The above point represents April 2008.

Let the system of equations be

mx + ny = 4

2mx + ny = 0

Substitute (4, 8) for x and y in the above equations.

4m + 8n = 4

8m + 8n = 0

Subtract both equations

4m - 8m = 4

This gives

-4m = 4

Divide by 4

m = -1

Substitute m = -1 in 8m + 8n = 0

-8 + 8n = 0

This gives

8n = 8

Divide by 8

n = 1

So, the system of equations is -x + y = 4 and -2x + y = 0

<h3>The graph of the system of equations</h3>

The system of equations is -x + y = 4 and -2x + y = 0

See attachment for the graph of the system of equation

<h3>Prove that the solution is (4, 8)</h3>

The above is represented in the (a) part of this solution

Verify that the solution is (4, 8)

We have:

-x + y = 4 and -2x + y = 0

Substitute (4, 8) for x and y in the above equations.

-4 + 8 = 4 --- true

-2*4 + 8 = 0 --- true

Both equations are true

Hence, the system of equations have been verified

Read more about system of equations at:

brainly.com/question/14323743

#SPJ1

6 0
2 years ago
Please help me answer these 3 questions. Also, please EXPLAIN how you got the answer because sometimes people answer but don't e
nirvana33 [79]

Answer:

3 and 4

Step-by-step explanation:

4. 28/105 is what it is trying to explain

3. -3/12 is what it is trying to explain

7 0
3 years ago
A straight line has slope 1 and goes through the points (0, -1) and (a,3). Find the value of a.
Gala2k [10]

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{a}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{a}-\underset{x_1}{0}}}~~=~~\stackrel{\stackrel{slope}{\downarrow }}{1}\implies \cfrac{3+1}{a}=1\implies 4=a

8 0
3 years ago
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