Answer:

Step-by-step explanation:
Given (AB )^T= B^T. A^T;
To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

Answer:
y=16(x)+7(y)
y=16 + 7
y=23
im not sure bc is nt info but i think i this
Step-by-step explanation:
1584 lightbulbs would be defective out of 4400