I need help will give a lot of credit and brainly if you tell me the right boxes and if it is correct FYI this is zearn

You have $20 to spend on taxi fare. The ride cost five dollars plus $2.50 per mile. M represent the number of miles Reading.writ

posledela

Well im not sure about that but I think the answer is 42.5

5 0

3 years ago

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If the mangos cost $20 per 10. how much did I spend on mangos

sashaice [31]

How many mangos are you buying?

7 0

3 years ago

So far this month John calculated that he will earn $40 in comission for his $500 in product sales. If John would like his comis

Helen [10]

John made $40 commissions for $500 sales or 40/500. He wants $320 for an unknown amount of sales or 320/x.

40/500=320/x Cross multiply.

40x=160,000

Divide both sides by 40.

X=4,000

He needs his sales to be $4,000 to get $320 in commission.

4 0

3 years ago

Explain what is meant by the equation lim x → 8 f(x) = 9. If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|. The valu

loris [4]

Complete Question

1 Explain what is meant by the equation lim x → 8 f(x) = 9.

A If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|.

B The values of f(x) can be made as close to 8 as we like by taking x sufficiently close to 9.

C f(x) = 9 for all values of x.

D If |x1 − 8| < |x2 − 8|, then |f(x1) − 9|≤ |f(x2) − 9|.

E The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8.

2 Is it possible for this statement to be true and yet f(8) = 6? Explain.

A Yes, the graph could have a hole at (8, 9) and be defined such that f(8) =6.

B Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6.

C No, if f(8) = 6, then lim x→8 f(x) = 6.

D No, if lim x→8 f(x) = 9, then f(8) = 9.

Answer:

1

The correct option is D

2

The correct option is A

Step-by-step explanation:

Generally a a limit function $\lim_{n \to x } f(x) = L$

Tell us that as n tends toward x the values of f(x) tends towards L hence for the first question E is the correct option

Now looking at the second question

Yes it is possible for lim x → 8 f(x) = 9. to be true and f(8) = 6 this is because the graph defined by this limit equation can have a hole the point

(8, 9) and created in such a way that f(8) = 6

7 0

3 years ago

Find the length of the radius of the circle whose perimeter is xcm and the area is

Jobisdone [24]

$\bf \stackrel{\textit{perimeter}}{\textit{circumference}}\textit{ of a circle}\\\\ C = 2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=x \end{cases}\implies x = 2\pi r\implies \boxed{\cfrac{x}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=x \end{cases}\implies x = \pi \left( \boxed{\cfrac{x}{2\pi }} \right)^2\implies x = \pi \cdot \cfrac{x^2}{2^2\pi^2}$

$\bf x = \cfrac{x^2}{4\pi }\implies 4\pi x = x^2\implies \cfrac{4\pi x}{x}=x\implies \blacktriangleright 4\pi = x\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since the radius is}}{r = \cfrac{x}{2\pi }}\implies r =\cfrac{4\pi }{2\pi }\implies \blacktriangleright r = 2\blacktriangleleft$

6 0

4 years ago

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