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3 years ago

G(n) = 2n^2 - 4n; Find g(-9)

Mathematics

1 answer:

rusak2 [61]3 years ago

6 0

Answer:

g(n) = 2n^2 - 4n; Find g(-9)

The answer is 170, because you have to plug in -9 for all the N values. When you do that, just follow PEMDAS.

P-Parentheses

E-Exponents

M-Multiplication

D-Division

A-Addition

S-Subtraction

Step-by-step explanation:

g(-9) = 2(-9)^2 - 4(-9)

g(-9) = 18^2 -4(-9)

g(-9) = 134+36

g(-9) = 170

I really hope this helps!

Sincerely,

Josiah Kumai

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A young couple purchases their first new home in 2011 for $95,000. They sell it to move into a bigger home in 2018 for $105,00

mart [117]

Given:

The value of home in 2011 is $95,000.

The value of home in 2018 is $105,000.

To find:

The exponential model for the value of the home.

Solution:

The general exponential model is

$y=ab^x$ ...(i)

where, a is initial value and b is growth factor.

Let 2011 is initial year and x be the number of years after 2011.

So, initial value of home is 95,000, i.e., a=95,000.

Put a=95000 in (i).

$y=95000b^x$ ...(ii)

The value of home in 2018 is $105,000. It means the value of y is 105000 at x=7.

$105000=95000b^7$

$\dfrac{105000}{95000}=b^7$

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Taking 7th root on both sides, we get

$\left(\dfrac{21}{19}\right)^{\frac{1}{7}}=b$

Put $b=\left(\dfrac{21}{19}\right)^{\frac{1}{7}}$ in (ii).

$y=95000\left(\left(\dfrac{21}{19}\right)^{\frac{1}{7}}\right)^x$

$y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}$

Therefore, the required exponential model for the value of home is $y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}$ , where x is the number of years after 2011.

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